Question

A dish washer manufacturer introduced a new type of dish washer and conducted a survey on the new product. The survey showed 40% of the consumers had seen an advertisement for the new product, 20% had tried the new product, and 15% had both seen an advertisement and tried the new product. Let event A denote that the consumers had seen an ad for the new product, and event B denote that the consumers had tried the new product. What is the probability a randomly selected consumer had either seen an advertisement or tried the new product

Answer 1

Answer:

$P(A \cup B) =0.45$

Step-by-step explanation:

From the question we are told that

Consumers seen the soap $P_A=40\% =0.40$

Consumers used the soap $P_B=20\% =0.2$

Consumers seen/tried the soap $P_x=15\% =0.15$

Generally the probability that consumers have seen and tried the soap is

$P(A \cup B=P(A)+P(B)-P(A \cap B$

$P(A \cup B=0.4+0.2-0.15$

$P(A \cup B) =0.45$