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galina1969 [7]
3 years ago
9

Which trigonometric ratios are correct for triangle XYZ? Check all that apply. tan(Y) = Eight-fifteenths cos(X) = Fifteen-sevent

eenths tan(X) = Fifteen-eighths sin(Y) = Eight-seventeenths cos(Y) =
Mathematics
2 answers:
Ne4ueva [31]3 years ago
7 0

Answer:

A, C, and D!

Step-by-step explanation:

got it correct on edge2021!

Sidana [21]3 years ago
4 0

Answer:

AAAAAA

Step-by-step explanation:

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What is cos(45°)?
Andrej [43]

Answer:

\rm \dfrac{\sqrt2}{2}

Step-by-step explanation:

A right angled ∆ is given to us and we need to find out the value of cos 45° ( with rationalized denominator ) . As we know that in a right angle ∆ , the value of cosine is ,

\rm\implies cos\theta =\dfrac{base}{hypotenuse}

In the given triangle ,

  • Value of base = 1
  • Value of hypotenuse = √2

On substituting the respective values ,

\rm\implies cos45^\circ =\dfrac{1}{\sqrt2}

For rationalizing the denominator , multiply numerator and denominator by √2 , we have,

\rm\implies cos45^\circ=\dfrac{1(\sqrt2)}{(\sqrt2)(\sqrt2)}

Simplify ,

\rm\implies \boxed{\pink{\frak{ cos45^\circ=\dfrac{\sqrt2}{2} }}}

6 0
3 years ago
Maria estimates college tuition and fees, room and board, books, and other charges total $10,100. She will receive a scholarship
garri49 [273]
Maria needs to save $187.50 per month in order to attend college. 

First, subtract the $1,100 scholarship from the cost of college, or $10,100, to get $9,000. This is the amount that she needs to save after 4 years. Next, since she is saving monthly, we need to know how many monthly periods are in 4 years, so multiply 12 months/year by 4 years to get 48 monthly periods. Finally, divide the total amount needed ($9,000) by the monthly periods (48) to get $187.50. This answer would change if she earned any interest on her savings, and depending on the compounding period, if any, for such interest. 
3 0
3 years ago
Ms. Gonzales gathered data on the number of vowels in the first and last names of each of her students. The data are shown in th
Svetllana [295]
Where s the data of the students
7 0
2 years ago
Math question need help with substation please?
Juliette [100K]

<em>2 solutions</em>

<em>X= 16</em>

<em>X=49</em>

Step-by-step explanation:

<em>original equation</em>

<em>x-11√x+28 = 0</em>

<em>   Isolate</em>

<em>     -11√x = -x-28+0</em>

<em>  Tidy up</em>

<em>     11√x = x+28</em>

<em>  Raise both sides to the second power</em>

<em>     (11√x)2 = (x+28)2</em>

<em>After squaring</em>

<em>     121x = x2+56x+784</em>

<em> Plug in 49 for  x </em>

<em>      11√(49) = (49)+28</em>

<em>Simplify</em>

<em>      11√49 = 77</em>

<em>      Solution checks !!</em>

<em>     Solution is:</em>

     x = 49

<em>Plug in 16 for  x </em>

<em>      11√(16) = (16)+28</em>

<em>Simplify</em>

<em>      11√16 = 44</em>

<em>      Solution checks !!</em>

<em>     Solution is:</em>

     x = 16

3 0
3 years ago
A coin is tossed and a single 6 sided number cube is rolled. Find the probability of landing on the heads side of the coin and r
Delicious77 [7]

Answer:

The probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

Step-by-step explanation:

Given:

Coin is tossed and a single 6 sided number cube is rolled.

Let the event of tossing head be 'H' and event of rolling a 3 be 'R3'.

Now, we know that:

Probability of an event 'A' = Favorable outcomes of 'A' ÷ Total possible outcomes

Now, for tossing a coin, the total possible outcomes are head and tail. So, there are 2 possible outcomes.

So, probability of event 'H' is given as:

P(H)=\dfrac{n(H)}{n(S)}\\\\P(H)=\frac{1}{2}=0.5

Similarly, for rolling a 6 sided cube, the possible outcomes are numbers 1 to 6. So, the number of possible outcomes is, n(S)=6

Now, probability of rolling a 3 is given as:

P(R3)=\frac{n(R3)}{n(S)}\\\\P(R3)=\frac{1}{6}

Now, both the events 'H' and 'R3' occur together. So, the combined probability is the product of two individual probabilities as they are independent events. So,

P(H\ and\ R3)=P(H)\times P(R3)\\\\P(H\ and\ R3)=\frac{1}{2}\times \frac{1}{6}\\\\P(H\ and\ R3)=\frac{1}{12}=0.083

Note: Independent events are those events whose intersection is an empty set of events or the outcome of one event doesn't affect the outcome of the other event.

Therefore, the probability of landing on the heads side of the coin and rolling 3 on the number cube is 0.083.

4 0
3 years ago
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