So
5*5*3*3*3=5²*3³
Prime factorization is 5²*3³
Answer=5²*3³
I=PRT/100
720=1000x9xT/100
72000=9000T
T=72000/9000
T=8years
<h3>
Answer: 4</h3>
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Explanation:
For now, ignore the variables. Let's just focus on the coefficients 12 and 16.
The GCF of 12 and 16 is 4 because this is the largest factor they have in common.
12 = 4*3
16 = 4*4
You could create a factor tree to get the prime factorization of each number
12 = 2*2*3
16 = 2*2*2*2
Each factor tree has two copies of '2' leading to the GCF 2*2 = 4.
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Now let's go back to the variables. The term 12n and 16w^3 do not have any variables in common. So the final answer won't have any variables in it. If both terms had say a 'w' in them, then w would somehow be involved in the GCF. But that's not the case here. So we just stick to 4 as our answer.
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Side note: If you had 12n+16w^3 and you wanted to factor, then you would factor out the GCF 4 to get 12n+16w^3 = 4(3n+4w^3). Use the distribution rule to confirm this.
Answer:
2 and 3
Step-by-step explanation:
2 squared = 4
3 squared = 9
5 lies between 4 and 9
Step-by-step explanation:
The simplest possible form of f(n) is:
f(n) = n² + bn + c
f(n) / (n + 1) has a remainder of -12, so:
n² + bn + c = (n + p) (n + 1) − 12
n² + bn + c = n² + (1 + p)n + p − 12
b = 1 + p and c = p − 12
f(n) / (n + 2) has a remainder of -24, so:
n² + bn + c = (n + q) (n + 2) − 24
n² + bn + c = n² + (2 + q)n + 2q − 24
b = 2 + q and c = 2q − 24
Setting the expressions equal:
1 + p = 2 + q and p − 12 = 2q − 24
1 = p − q and p = 2q − 12
Solving the system of equations:
1 = q − 12
q = 13
p = 14
b = 15, c = 2
Therefore, f(n) is:
f(n) = n² + 15n + 2
Using grouping:
f(n) = n² + 3n + 2 + 12n
f(n) = (n + 1) (n + 2) + 12n
f(n) / ((n + 1) (n + 2) = 1 + (12n) / ((n + 1) (n + 2))
The remainder is 12n.