Question

This Question: 1 pt Find the sum of the sequence. 47 +48 +49 +50 + ... + 136 The sum is Enter your answer in the answer box.

Answer 1

Answer:

The sum is $8235$.

Step-by-step explanation:

You can use the result that establishes that the sum of the first $n$ natural numbers is given by the formula:

$1+2+3+4+\cdots + (n-1)+ n= \dfrac{n(n+1)}{2}$.

So, if you have to calculate the sum of the natural numbers from 47 to 136 you can sum from 1 to 136, then subtract the sum from 1 to 46. That is to say,

$47+48+49+50+\cdots+136=(1+2+3+\cdots+46+47+\cdots +136)-(1+2+3+\cdots +46)$.

Using the given formula  we have:

$47+48+49+50+\cdots+136=\dfrac{136\cdot 137}{2}-\dfrac{46\cdot 47}{2}=9316-1081=8235$.

Answer 2

Answer:

the other pereson oits righgt

Step-by-step explanation: