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Novosadov [1.4K]
3 years ago
11

Han is in training for a marathon. One day, Han ran 8 miles. The next day, he plans to run that same distance plus half as much

again. How far does Han plan to run the next day? *
Mathematics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

hen is in training of Marathon Vande hand run 8 Miles next day he plans to run the same I bless have much so how far does he planned

Step-by-step explanation:

the hendrun 8 and half miles the next radio Follow Me animal lover

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A deposit of $1,295 at 7% for 180 days what is the interest earned
wariber [46]
The formula is
I=prt
I interest earned?
P principle 1295
R interest rate 0.07
T time 180/365
I=1,295×0.07×(180÷365)
I=44.70
7 0
3 years ago
All the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over. After 60 additional boxe
AveGali [126]

Answer:

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

Step-by-step explanation:

Given that all the boxes in a certain warehouse were arranged in stacks of 12 boxes each, with no boxes left over.

This implies that boxes are in multiples of 12

i.e. 12, or 24, or 36 or....

Let us say this as 12m for m an integer

Now additional boxes arrived =60

Total number of boxes now = 12m+60

This when arranged in stacks of 14,nothing left out

Or this is multiple of 14

12m+60 = 14n for some positive integer n.

By trial and error we find that if 60 is to be divided by 14, 24 should be added and 24 is a multiple of 12.

So we say originally 24 boxes were there now 84 boxes there.

Hence both options are right.

(1) There were fewer than 110 boxes in the warehouse before the 60 additional boxes arrived. (2) There were fewer than 120 boxes in the warehouse after the 60 additional boxes arrived.

3 0
3 years ago
beni is shopping for a new cell phone plan. company a charges$72.25for a new phone and $85.50 per month.company b charges $151.2
tigry1 [53]
Missing questions and subsequent solutions:
(a) Write an equation for company A for cost, C, number of months, n, that Beni will pay for the phone.

Solution:
For company A:
C = 72.25 + 85.50n

(b) Write an eqyation for company B for cost, C, and number of months, n, that Bei will pay for the phone.

Solution:
For company B:
C = 151.25 + 65.75n

(c) Write an inequality when the cost from company A is better than cost from company B.

Solution:
72.25 + 85.50n ≤ 151.25 + 65.75n
(85.50-65.75)n ≤ (151.25 - 72.25)
19.75 n ≤ 79
n ≤ 4

(d) Value of n for which cost from the two companies will be the same.

Solution:
If cost for companies A and B are the same, then
72.25 + 85.50n = 151.25 + 65.75n
(85.5 - 65.75)n = 151.25 - 72.25
19.75n = 79
 n = 79/19.75 = 4 months

After 4 months,
C = 72.25 + 85.5*4 = $414.25
7 0
3 years ago
Suppose that a student has $150 in a band savings account at the start of the school year. Calculate the change in that savings
Roman55 [17]
150 12 x 10=120+150= 270
4 0
3 years ago
A sign at a store reads "3 notebooks for $6". What is the price per note book
mojhsa [17]
$2 per notebook would be the correct answer
3 0
4 years ago
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