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3 years ago

5

PLEASE HELP ME ASAP!

1 answer:

Zanzabum3 years ago

7 0

The answer is eighty/ eighty-two

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Factor out the greatest common factor<br> 15x^2-21x<br> ^=exponent

gavmur [86]

Answer:

3x

Step-by-step explanation:

3x(5x-7)

brainliest!

4 0

2 years ago

Let P be a point between points S and T on 2004-01-01-02-00_files/i0120000.jpg. If ST = 21, SP = 3b – 11, and PT = b + 4, solve

NNADVOKAT [17]

The best and most correct answer among the choices provided by your question is the third choice or letter C.

<span>If ST = 21, SP = 3b – 11, and PT = b + 4, the value of b would be 14.

</span>
I hope my answer has come to your help. God bless and have a nice day ahead!

7 0

2 years ago

Read 2 more answers

Someone pleeeeaseeee help a sister out

zvonat [6]

I gottt you sis

P + 0.20p = 1.20p

P - 0.20p = 0.80p

P + 1/4p = 5/4p

P - 1/4p = 3/4p

7 0

2 years ago

2^(n-1) = 256 ? Please give me the answer

klemol [59]

Answer:

n = 9

Step-by-step explanation:

Note that

256 = $2^{8}$ , thus

$2^{n-1}$ = $2^{8}$

Since the bases on both sides are equal (2) equate the exponents

n - 1 = 8 ( add 1 to both sides )

n = 9

7 0

2 years ago

Rewrite the polynomial-9x^5+36x^4+189x^3 in factored form, using the factoring method method you prefer.

ozzi

The polynomial 9x^5+36x^4+189x^3 in factored form is $-9 x \times x \times x \times(x-7) \times(x+3)$

<u>Solution:</u>

Given, polynomial equation is $-9 x^{5}+36 x^{4}+189 x^{3}$

We have to find the factored form of the above given polynomial equation.

Let us solve it by grouping.

Now, take the polynomial ⇒ $-9 x^{5}+36 x^{4}+189 x^{3}$

By taking common term out, we get

$\rightarrow-9 x^{3}\left(x^{2}-4 x-21\right)$

$\rightarrow-9 x^{3}\left(x^{2}-(7-3) x-7 \times 3\right)$

Grouping the terms we get,

$\rightarrow-9 x^{3}\left(\left(x^{2}-7 x\right)+(3 x-7 x^3)\right)$

Taking common terms out from each group,

$\rightarrow-9 x^{3}(x(x-7)+3(x-7))$

$\Rightarrow-9 x^{3}((x-7)(x+3))$

$\rightarrow-9 x \times x \times x \times(x-7) \times(x+3)$

Thus the factored form of polynomial is found out

4 0

3 years ago