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3 years ago

PLEASE HELP ME ASAP!

Mathematics

1 answer:

Zanzabum3 years ago

7 0

The answer is eighty/ eighty-two

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Fast forward to the moment after the two outermost recursive calls complete, but before the final Merge step. Thinking of the tw

adoni [48]

Answer:

The answer is 2.

Step-by-step explanation:

1- Suppose we have following array of ten integers: 5 3 8 9 1 7 0 2 6 4.

2- Before the last merge, the left half and the right half must be sorted. So it should be

1 3 5 8 9 0 2 4 6 7

Therefore the solution is 2.

4 0

2 years ago

How to round 4.66 to the nearest hundredth

andrey2020 [161]

To round it to the nearest hundreth, round the 6 to the nearest number. 1-4 means round to the lowest number in the chart. 6-10 means round to the nearest number above the current number. The answer would be 4.7

5 0

3 years ago

Plz help!! And show work plz 18 points!

garri49 [273]

75√109.5=1.46
1.2√79.1=65.92
5.2√9.16=1.76
17.1 =17.1

4 0

2 years ago

What is the answer for this please 23÷23

baherus [9]

Answer:

Step-by-step explanation:

Any number divided by itself equals 1. So, 23 divided by 23 is 1.

8 0

1 year ago

An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample

valentina_108 [34]

Answer:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

Replacing we got:

$\bar X=58.875$ represent the mean

$s=5.083$ represent the sample standard deviation for the sample

$n=8$ sample size

$\mu_o =60$ represent the value that we want to test

$\alpha=0.1$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info we got:

$t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626$

The degrees of freedom are given by:

$df=n-1=8-1=7$

The p value would be given by:

$p_v =P(t_{(7)}$

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0

2 years ago