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3 years ago

Dani wants to create a web page to document her travel adventures. Which coding language should she use? HTML Java Python Text

Computers and Technology

1 answer:

Anna [14]3 years ago

7 0

Answer:

HTML, CSS, JavaScript, python, SQL

Explanation:

To create a web page for her travel adventures Dani has to use HTML and CSS to design the page's layout. A beautiful simple design such as one which shows photos of her on her travel destinations, and a paragraph for her to write a little story on her travels would do.

Dani needs JavaScript to animate the photos she's going to post on the page. Dani also should use python to build the backend of her page so she can write codes to save and access her documented adventures from the database. She should use a database language like SQL to save all of her adventures so she can view them at a later time for the memories.

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Which of the following is not a basic networking hardware component? Network interface card

RideAnS [48]

Answer:

Device Driver

Explanation:

All of the other options are physical and are something that you can physically touch. The device driver runs in software and allows the computer to communicate with the device that is attached.

4 0

3 years ago

There are n poor college students who are renting two houses. For every pair of students pi and pj , the function d(pi , pj ) ou

Nuetrik [128]

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:- n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex u ∈ V

$\rightarrow$ for each vertex v ∈ V

$\rightarrow\rightarrow$ if( d(pu, pj) > k )

$\rightarrow\rightarrow\rightarrow$ add vertex u to Adj[v] // Adj[v] represents adjacency list of v

$\rightarrow\rightarrow\rightarrow$ add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3. bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

$\rightarrow$ visited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph

6. for each vertex u ∈ V

$\rightarrow$ if ( visited[u] == false)

$\rightarrow\rightarrow$ color[u] = 0;

$\rightarrow\rightarrow$ isbipartite = BFS(G,u,color,visited) // if the vertices reachable from u form a bipartite graph, it returns true

$\rightarrow\rightarrow$ if (isbipartite == false)

$\rightarrow\rightarrow\rightarrow$ print " No solution exists "

$\rightarrow\rightarrow\rightarrow$ exit(0)

7. for each vertex u ∈V

$\rightarrow$ if (color[u] == 0 )

$\rightarrow\rightarrow$ print " Student u is assigned Bus 1"

$\rightarrow$ else

$\rightarrow\rightarrow$ print " Student v is assigned Bus 2"

BFS(G,s,color,visited)

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

$\rightarrow$ u = Q.pop()

$\rightarrow$ for each vertex v ∈ Adj[u]

$\rightarrow\rightarrow$ if (visited[v] == false)

$\rightarrow\rightarrow\rightarrow$ color[v] = (color[u] + 1) % 2

$\rightarrow\rightarrow\rightarrow$ visited[v] = true

$\rightarrow\rightarrow\rightarrow$ Q.push(v)

$\rightarrow\rightarrow$ else

$\rightarrow\rightarrow\rightarrow$ if (color[u] == color[v])

$\rightarrow\rightarrow\rightarrow\rightarrow$ return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

3 0

3 years ago

What is the fundamental goal of outsourcing? increased quality brand expansion cultural diversity cost savings

galben [10]

Answer:

Cost saving is the fundamental goal of outsourcing.

Explanation:

Initially the companies where outsourcing task only for Cost cutting. But nowadays, the companies do that for so many other reasons like, increase the efficiency, reducing overhead, to concentrate on core business peacefully, to obtain more profit, etc.

The cultural diversity does not affect or make companies to outsource.

We can indirectly increase the quality but it is not the primary goal of outsourcing.

Brand expansion will holds good, only the BPO is run under the name of the company. But this is once again not the major objective.

7 0

3 years ago

Write a program that accepts any number of homework scores ranging in value from 0 through 10. Prompt the user for a new value i

vazorg [7]

Answer:

This program is written in C++

Note that the average is calculated without the highest and the least value.

Comments are used for explanatory purpose

See attachment for .cpp file.

Program starts here

#include<iostream>

using namespace std;

int main()

{

int num;

cout<<"Enter Number of Test [0-10]: ";

//cin>>num;

while(!(cin>>num) || num > 10|| num<0)

{

cout << "That was invalid. Enter a valid digit: "<<endl;

cin.clear(); // reset the failed input

cin.ignore(123,'\n');//Discard previous input

}

//Declare scores

int scores[num];

//Accept Input

for(int i =0;i<num;i++)

{

cout<<"Enter Test Score "<<(i+1)<<": ";

cin>>scores[i];

}

//Determine highest

int max = scores[0];

for (int i = 1; i < num; i++)

{

if (scores[i] > max)

{

max = scores[i];

}

//Determine Lowest

int least = scores[0];

for (int i = 1; i < num; i++)

{

if (scores[i] < least)

{

least = scores[i];

}

int sum = 0;

//Calculate total

for(int i =0; i< num;i++)

{

sum += scores[i];

}

//Subtract highest and least values

sum = sum - least - max;

//Calculate average

double average = sum / (num - 2);

//Print Average

cout<<"Average = "<<average<<endl;

//Print Highest

cout<<"Highest = "<<max<<endl;

//Print Lowest

cout<<"Lowest = "<<least;

return 0;

}

Download cpp

8 0

4 years ago

Renita manages a cell-phone store. She often needs to send contracts to business customers who are far away. Renita is most like

vesna_86 [32]

Answer:

a fax machine.

I hope it helps.

7 0

3 years ago