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lyudmila [28]
2 years ago
8

PLEASE PLEASE PLEASE PLEASE help me Im completly lost will give brainliest and 50 points

Computers and Technology
2 answers:
uranmaximum [27]2 years ago
4 0

It is unclear if the octopus is real or a myth
pav-90 [236]2 years ago
3 0

It can be either a or b.. I suggest go with b

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The ________ view in access looks similar to an excel spreadsheet.
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Write a function: function solution(N); that, given a positive integer N, prints the consecutive numbers from 1 to N, each on a
koban [17]

Answer:

<em>The program written in Python is as follows:</em>

def solution(N):

     concat = ""

     for i in range(1,N+1):

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

           else:

                 if i%2 == 0:

                       concat= concat+"Codility"

                 if i%3 == 0:

                       concat= concat+"Testers"

                 if i%5 == 0:

                       concat= concat+"Coders"

                 print(concat)

                 concat = ""

N = int(input("Enter a positive integer: "))

solution(N)

Explanation:

This line declares the function

def solution(N):

This line initializes a variable named concat to an empty string

     concat = ""

This line iterates from 1 to the input integer

     for i in range(1,N+1):

<em>This line checks if the current number of iteration is divisible by 2,3 or 5, if no, the number is printed</em>

           if not(i%2 == 0 or i%3 ==0 or i%5 == 0):

                 print(str(i))

<em>If otherwise</em>

           else:

<em>This lines checks if current number is divisible by 2; if yes the string "Codility" is concatenated to string concat</em>

                 if i%2 == 0:

                       concat= concat+"Codility"

<em>This lines checks if current number is divisible by 3; if yes the string "Testers" is concatenated to string concat</em>

<em>                 </em> if i%3 == 0:

                       concat= concat+"Testers"

<em>This lines checks if current number is divisible by 2; if yes the string "Coders" is concatenated to string concat</em>

                 if i%5 == 0:

                       concat= concat+"Coders"

<em>The concatenated string is printed using this line</em>

                 print(concat)

This variable concat is intialized back to an empty string

                 concat = ""

The main method starts here

N = int(input("Enter a positive integer: "))

This line calls the defined function solution

solution(N)

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