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MrRa [10]
3 years ago
10

What is the value of x?

Mathematics
2 answers:
Juliette [100K]3 years ago
7 0

Answer:

x=3

Step-by-step explanation:

schepotkina [342]3 years ago
4 0

Answer:

x=3

Step-by-step explanation:

took the quiz

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What is the slope of this graph?<br> 0.3<br> -3<br> los<br> 1<br> 3<br> 3<br> 1<br> 2 3 4 5
iren2701 [21]

Answer:

A

Step-by-step explanation:

Use the formula rise/run. The rise, in this case, was 3 and the run was 1. There for it would be 3/1 which is simplified to 3.

3 0
3 years ago
What is the surface area (in square meters) of a box with length of 3 m, width of 4 m and a height of 2 m? Round to the nearest
djyliett [7]

Answer:

C) 52

Step-by-step explanation:

=  2x 4x  3x  2x  3x  2x  4

Hope this helps!

4 0
3 years ago
A car seller buys a car from a manufacturer for $8,000. He increases the cost by 6 percent. What is the markup value?
kakasveta [241]
Hello, 

do you know what 6% equals in decimal? 

With such information, all you must do is multiply the decimal value of 6% to 8000, then add that value to 8000 for the markup value. 

4 0
4 years ago
15.What is the area of the segment?
Strike441 [17]

Answer:

The Area of a Segment is the area of a sector minus the triangular piece (shown in light blue here). There is a lengthy reason, but the result is a slight modification of the Sector formula: Area of Segment = θ − sin(θ) 2 × r2 (when θ is in radians) Area of Segment = ( θ × π 360 − sin(θ)2 ) × r2 (when θ is in degrees)

Step-by-step explanation:

6 0
3 years ago
Hello, help me please)
AlladinOne [14]

Answer:

Given equation:

10^{5x-2}=2^{8x-3}

Take natural logs of both sides:

\implies \ln 10^{5x-2}= \ln 2^{8x-3}

\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax

\implies (5x-2)\ln 10=(8x-3) \ln 2

Expand brackets:

\implies 5x\ln 10 - 2\ln 10=8x \ln 2 -3 \ln 2

Collect like terms:

\implies 5x\ln 10 - 8x \ln 2 =2\ln 10-3 \ln 2

Factor left sides:

\implies x(5\ln 10 - 8 \ln 2) =2\ln 10-3 \ln 2

\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax

\implies x(\ln 10^5 - \ln 2^8) =\ln 10^2- \ln 2^3

\textsf{Apply log Quotient law}: \quad \ln_a\frac{x}{y}=\ln_ax - \ln_ay

\implies x\left(\ln\left(\dfrac{10^5}{2^8}\right)\right) =\ln\left(\dfrac{10^2}{2^3}\right)

Simplify:

\implies x\left(\ln\left(\dfrac{3125}{8}\right)\right) =\ln\left(\dfrac{25}{2}\right)

\implies x=\dfrac{\ln\left(\dfrac{25}{2}\right)}{\ln\left(\dfrac{3125}{8}\right)}

\implies x=0.4232297737...

6 0
2 years ago
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