Step-by-step explanation:
(F-32)* 5/9 = C
(83 -32) * 5/9 = 28 + 1/3
s = number of standard downloads
2s = number of high-quality downloads
2.8s + 4.6(2s) = 2760
2.8s + 9.2s = 2760
12s = 2760
s = 230
The standard version was downloaded 230 times and the high-quality version was downloaded 460 times.
Step-by-step explanation:
<h3><u>1</u><u>(</u><u>r</u><u>+</u><u>7</u><u>)</u> - 9×s</h3><h3>5</h3>
again, take LCM
<h3><u>r</u><u>+</u><u>7</u><u> </u><u>-</u><u>5</u><u> </u><u>(</u><u>9</u><u>s</u><u>)</u></h3><h3> 5</h3>
<h3><u>r</u><u>+</u><u>7</u><u>-</u><u>4</u><u>5</u><u>s</u></h3><h3> 5</h3>
The standard joint variation is y = kxz, so we modify it for this one and get j = kgv. Since we don't know the constant, I'm assuming it's 1
This gives us j = gv, or j =10*9 = 90
Answer:
30 kilograms, I suppose. If there are 5 packages that each weight 6 kilograms, then that's 5 6 kilograms, which may equal 30 in all.