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nexus9112 [7]
3 years ago
5

What is the absolute value [-5.6]

Mathematics
2 answers:
Sav [38]3 years ago
8 0

Answer:

5.6

Step-by-step explanation:

Just take the negative sign out and you have your answer, because you can't have a negative answer as a absolute value.

Hope this helps!!! :D

attashe74 [19]3 years ago
7 0

Answer:

5.6 brainlist plz

Step-by-step explanation:

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I believe the answer is 21
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The normal body temperature of a camel is 37°C. This temperature varies by up to 3°C throughout the day. Write and solve an abso
uysha [10]

The normal body temperature : to = 37° C
An inequality is:
| t - to | ≤ 3
| t - 37 | ≤ 3
t - 37 ≤ 3     AND  ( - t - 37 ) ≤ 3
t ≤ 3 + 37               - t + 37 ≤ 3
t ≤ 40                     - t ≤ 3 - 37
                              - t ≤ - 34   / *( - 1 )
                                t ≥ 34
Answer t <span>∈ [</span><span>  34</span><span>°C,</span><span>  40</span><span>° C ]</span>.

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3 years ago
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6 0
4 years ago
How long would it take you to double your money is the bank pays 3.6% interest, compounded
Lapatulllka [165]

Answer:

t=19.25\ years

Step-by-step explanation:

we know that

The formula to calculate continuously compounded interest is equal to

A=P(e)^{rt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest in decimal  

t is Number of Time Periods  

e is the mathematical constant number

we have  

t=?\ years\\P=x\\r=3.6\%=3.6/100=0.036\\A=2x  

substitute in the formula above

2x=x(e)^{0.036t}  

solve for t

simplify

2=(e)^{0.036t}  

Apply ln both sides

ln(2)=ln[(e)^{0.036t}]

Applying property of exponents

ln(2)=[0.036t]ln(e)

Remember that ln(e) =1

ln(2)=[0.036t]

t=ln(2)/[0.036]

t=19.25\ years

7 0
4 years ago
Find the area of this figure. use 3.14 for pi.​
Ganezh [65]
The square would be 100.
The semicircle you will use the formula πr^2/2.
That would mean you would take the 3.14x5^2/2.
(3.14x5x5)/2
(3.14x25)/2
78.5/2
=39.25
So the total area would be 139.25
7 0
3 years ago
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