Answer:
The solutions for the given system of equations are:
Step-by-step explanation:
Given the equation system:
We obtain the following matrix:
![\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%261%264%26-3%5C%5C-1%261%264%2617%5Cend%7Barray%7D%5Cright%5D)
<u>Step 1:</u> Multiply the fisrt row by 1/3.
![\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B3%7D%20%26%5Cfrac%7B4%7D%7B3%7D%26-1%5C%5C-1%261%264%2617%5Cend%7Barray%7D%5Cright%5D)
<u>Step 2:</u> Sum the first row and the second row.
![\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B3%7D%20%26%5Cfrac%7B4%7D%7B3%7D%26-1%5C%5C0%26%5Cfrac%7B4%7D%7B3%7D%20%26%5Cfrac%7B16%7D%7B3%7D%2616%5Cend%7Barray%7D%5Cright%5D)
<u>Step 3:</u> Multiply the second row by 3/4.
![\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B3%7D%20%26%5Cfrac%7B4%7D%7B3%7D%26-1%5C%5C0%261%20%264%2612%5Cend%7Barray%7D%5Cright%5D)
<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.
![\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%20%260%26-5%5C%5C0%261%20%264%2612%5Cend%7Barray%7D%5Cright%5D)
The result of the reduced matrix is:
This is equal to:
These are the solutions for the system of equations in terms of z, where z can be any number.
Answer:
There's no direct variation
Step-by-step explanation:
Required
Determine if there's a direct variation between the number and its position
I'll start by giving an illustration of how the triangle is represented using stars (*)
*
**
***
****
*****
Represent the line number with y and it's position with x
On line 1:
y = 1, x = 1
On line 2:
y = 2, x = 3
On line 3:
y = 3, x = 6
On line 4:
y = 4, x = 10
On line 5:
y = 5, x = 15
Note that, x is gotten by calculating the accumulated number of stars while y is the line number.
Direct variation is represented by
y = kx
Or
kx = y
Where k is the constant of variation
For line 1:
Substitute 1 for y and 1 for x
k * 1 = 1
k = 1
For line 2:
Substitute 2 for y and 3 for x
k * 3 = 2
Divide through by 3
k = ⅔
Note that the values of k in both computations differ.
This implies that there's no direct variation and there's no need to check further.
Answer:
B
Step-by-step explanation:
There are no repeating values for x, for different values plugged in for y.
Step-by-step explanation:
• no solution:
3x+9+4x+x = 8x + 9
• one solution:
3x+9+4x+x = 7x + 11
• infinitely many solutions:
3x+9+4x+x = 8x + 11
She would weigh 48.98
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