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3 years ago

Which model completes this equation? = ?

Mathematics

2 answers:

hodyreva [135]3 years ago

8 0

Answer:

The model that has 2 blue slices filled.

Explanation:

In the first circle, there are 4/10 blue slices filled. In the second circle, there are 2/10 purple slices filled.

4/10 - 2/10 = 2/10

Therefore, your answer is 2/10 shaded blue.

ohaa [14]3 years ago

8 0

the 2nd one (right of the one that is full)

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Help...................

melisa1 [442]

Answer:

10.63cm

Step-by-step explanation:

Pythagorean theorem

a^2+b^2=c^2

(square root of 32)^2+(9)^2=113^2

The square root of 113 is 10.63.

I hope this helps :)

5 0

3 years ago

The polynomial f(x) is written in factored form:

qaws [65]

Answer:

x = 6, x = -5, x = 9

if f(x)=(x-6)(x+5)(x-9)

Step-by-step explanation:

The zeros of a polynomial in factored form can be found by setting the polynomial equal to zero and then realizing if a product is zero, then at least one of it's factors is zero.

So we have the zero's are the x's that satisfy

(x-6)(x+5)(x-9)=0.

We just need to solve three equations:

x-6=0

This can be solved by adding 6 on both sides: x=6

x+5=0

This can be solved by subtracting 5 on both sides: x=-5

x-9=0

This can be solved by adding 9 on both sides: x=9

The solutions are in { 6,-5,9 }.

7 0

4 years ago

Read 2 more answers

Find the x- and y- intercept of the line. -4x +2y =24

andrey2020 [161]

-4x +2y =24

x-intercept
y=0, -4x =24, x= - 6

(-6,0)

y-intercept
x=0, 2y=24, y=12

(0, 12)

4 0

4 years ago

Read 2 more answers

(1.25-0.4)/7+4x3

Natasha_Volkova [10]

Answer:

You should do multiplication first (PEMDAS)

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Which is the following is the set of real zeros of the function f(x) = (x3 + 1000)(x4 - 160,000)?

marusya05 [52]

Answer:

A. { -20, -10, 20 }

Step-by-step explanation:

Given:

The function is given as:

$f(x)=(x^3+1000)(x^4-160000)$

Let us simplify the function.

First, we use the identity $a^3+b^3=(a+b)(a^2-ab+b^2)$

$x^2+1000= x^3+10^3=(x+10)(x^2-10x+10^2)\\x^3+1000=(x+10)(x^2-10x+100)$

Next, we use the identity $a^4-b^4=(a-b)(a+b)(a^2+b^2)$

$x^4-160000=x^4-20^4=(x-20)(x+20)(x^2+20^2)=(x-20)(x+20)(x^2+400)$

Now, the function can be rewritten as:

$f(x)=(x+10)(x^2-10x+100)(x-20)(x+20)(x^2+400)$

Now, the zeros are those values of $x$ for which $f(x)=0$

Now, for $f(x)=0$ , we must have either of the factors 0.

$x+10=0\\x=-10$

$x-20=0\\x=20\\\\x+20=0\\x=-20$

The factors $x^2-10x+100$ and $x^2+400$ can have no zeros as the first one has imaginary roots and second one is always greater than 0 irrespective of the $x$ values.

So, the possible set of zeros are { -20, 10, 20 }.

6 0

4 years ago