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3 years ago

In which quadrants do solutions for the inequality y is less than or equal to two sevenths times x plus 1 exist?

Mathematics

1 answer:

hram777 [196]3 years ago

5 0

Answer:

y will be in every single quadrant

Step-by-step explanation:

So we have the equation $y\leq \frac{2}{7} x+1$ first we will have to look at the equation. It says that y is less than or equal to $\frac{2}{7} x+1$ since y is less than $\frac{2}{7} x+1$ the only place the shaded area where y can be is under the line that is drawn be the equation. When the equation is graphed the y-intercept will be on positive 1 it since slope is rise over run it will look something like the file attached to this. so under the line you can see every single quadrant so that is why it would be that way

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Let f be the function given by f(x) = x+4(x−1)(x+3) on the closed interval [−5,5]. On which closed interval is the function f gu

Vlad [161]

Answer:

Step-by-step explanation:

f(x)=x+4(x^2+2x-3)=4x^2+9x-12

f'(x)=8x+9

f'(x)=0,gives x=-9/8

f(-5)=-5+4(-5-1)(-5+3)=-5+4*-6*-2=43

f(-9/8)=-9/8+4(-9/8-1)(-9/8+3)

=-9/8+4*-17/8*15/8

=-9/8-255/16

=-273/16=-17 1/16

f(5)=4*5^2+9*5-12=100+45-12=133

absolute maximum=133

absolute minimum=-17 1/16

6 0

3 years ago

Suppose a casino invents a new game that you must pay $250 to play. The game works like this: The casino drawsrandom numbers bet

Ira Lisetskai [31]

Answer:

clc%clears screen

clear all%clears history

close all%closes all files

p=250;

M=[];

for i=1:100000

re=0;

S=0;

while(S<=1)

S=S+rand;

re=re+100;

end

M(i)=re;

end

disp('Expected received money is');

mean(M)

disp('Since expcted is greater than what we pay. So, we will play')

Step-by-step explanation:

6 0

3 years ago

A square has a side length of 21 + 11s. Select TWO equivalent

Misha Larkins [42]

Answer:

I choose option c hope it helps

4 0

3 years ago

The number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9 is . The probabi

Tems11 [23]

Answer:

1/15

Step-by-step explanation:

When we form such three-digit numbers with distinct digits using the digits 1 , 2 , 3 , 5 , 8 and 9 (in all six digits all different), observe that the order of digits does matter. For example, if we make a number using digits 1 , 2 , and 3 , we can have 123 , 132 , 231 , 213 , 312 or 321 .

Hence we have to find number of 3 digit numbers that can be made from these six digits using permutation and answer is ⁶ P ₃ = 6 × 5 × 4 = 120 .

.How haw many of them will have first digit as even, we have two choices 2 and 8 . Once we have chosen 2

for hundreds place, we can have only 8 in units place and any one of remaining 4 can be used in tens place. Hence four choices, with 2 in hundreds place and another four choices when we have 8 in hundreds place (and 2 in units place) i.e. total 8 possibilities.

Hence, the probability, that both the first digit and the last digit of the three digit number are even numbers, is 8 /120 = 1 /15

4 0

3 years ago

How do I find x and y

Usimov [2.4K]

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3 0

3 years ago