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3 years ago

Write an algorithm and draw flowchart to print 30 terms in the following sequence

Computers and Technology

1 answer:

valina [46]3 years ago

3 0

Answer:

I don't know what language you're using, so I'll write it in javascript which is usually legible enough.

console.log(buildSequence(30));

function buildSequence(maxVal){

maxVal = Math.abs(maxVal);

var n, list = [];

for(n = 1; n < maxVal; n++){

to check for odd numbers, we only need to know if the last bit

is a 1 or 0:

if(n & 1){ // <-- note the binary &, as opposed to the logical &&

list[list.length] = n;

}else{

list[list.length] = -n;

}

return list.implode(',');

}

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An acceptable website design is one that meets

Harman [31]

Answer:

i'd say b

Explanation:

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what is created when the movement of light is blocked by an object and cannot pass through the other side?

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A shadow is created.

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Which of the following systems is designed with full-time monitoring tools that search for patterns in network traffic to identi

kvasek [131]

Answer:

B. Intrusion Detection Software (IDS)

Explanation:

An Intrusion Detection Software (IDS) is designed to monitor all inbound and outbound network activity and identify any suspicious patterns that may indicate a network or system attack from someone attempting to break into or compromise a system. IDS is considered to be a passive-monitoring system, since the main function of an IDS product is to warn you of suspicious activity taking place − not prevent them. An IDS essentially reviews your network traffic and data and will identify probes, attacks, exploits and other vulnerabilities. IDSs can respond to the suspicious event in one of several ways, which includes displaying an alert, logging the event or even paging an administrator. In some cases the IDS may be prompted to reconfigure the network to reduce the effects of the suspicious intrusion.

3 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

a. displays the sum of all even numbers between 2 and 100 (inclusive). b. displays the sum of all squares between 1 and 100 (inc

LuckyWell [14K]

Answer:

The program required is in the explanation segment.

Explanation:

Program :

import math

# a. displays the sum of all even numbers between 2 and 100 (inclusive).

print("All even numbers from 2 to 100 inclusive ")

sum=0

i=2

while i<=100:

if i %2 ==0:

sum=sum+i

print(i,end=" ")

i=i+1

print("\nThe sum of all even numbers between 2 and 100 (inclusive) :",sum);

#b. displays the sum of all squares between 1 and 100 (inclusive).

print("\nAll squares numbers from 1 to 100 inclusive:")

i=1

sum=0

while i<=100:

print(i*i,end=" ")

i=i+1

sum=sum+(i*i)

print("\n\nThe sum of all squares between 1 and 100 (inclusive) is :",sum)

#c. displays the powers of 2 from 1 up to 256.

print("\nAll powers of 2 from 2 ** 0 to 2 ** 8:")

i=0

while True:

p=math.pow(2,i)

if p>256:

break

print("2 ** ",i," is ",int(p))

i=i+1

#d. displays the sum of all odd numbers between a and b (inclusive), where a and b are inputs

print("\nCompute the sum of all odd integers between two intgers ")

a=int(input("Enter an integer:"))

b=int(input("Enter another integer: "))

count = 0

temp=a

sum=0

while a<=b:

if a%2!=0:

print(a,end=" ")

sum=sum+a

a=a+1

print("\nThe total of the odd numbers from ", temp ," to ", b ,"is",sum)

#e.displays the sum of all odd digits of an input. (For example, if the input is 32677, the sum would be 3 + 7 + 7 = 17.)

print("\nCompute the sum of the odd digits in an integer ")

n=int(input("Enter an integer:"))

count=0

sum=0

temp=n

while n!=0:

rem = n%10

if rem%2!=0:

sum=sum+rem

count=count+1

n=int(n/10)

print("Sum of the odd digits is ",sum)

print("The total of the odd digits in ",temp," is ",count)

4 0

3 years ago