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algol [13]
3 years ago
13

Write an algorithm and draw flowchart to print 30 terms in the following sequence

Computers and Technology
1 answer:
valina [46]3 years ago
3 0

Answer:

/*

I don't know what language you're using, so I'll write it in javascript which is usually legible enough.

*/

console.log(buildSequence(30));

function buildSequence(maxVal){

   maxVal = Math.abs(maxVal);

   var n, list = [];

   for(n = 1; n < maxVal; n++){

       /*

        to check for odd numbers, we only need to know if the last bit

        is a 1 or 0:

       */

       if(n & 1){ // <-- note the binary &, as opposed to the logical &&

           list[list.length] = n;

       }else{

           list[list.length] = -n;

       }

   }

   return list.implode(',');

}

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Tema [17]

Answer:

Code is provided in the attachment form

Explanation:

Vector Multiplication code:

Vector_multiplication.c file contains C code.

See attachment no 1 attached below

Classification of Algorithm: For creating elements in vector c of size n, number of scalar  multiplications is equal to n. The size of original two vectors scales directly with the number of  operations. Hence, it is classified as O(n).

7 0
3 years ago
To keep you from inadvertently moving controls as you work in the IDE, click the form or control, then click the _________ optio
Alenkinab [10]

Answer:

Lock controls

Explanation:

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Write a program that reads three numbers and prints "increasing" if they are in increasing order, "decreasing" if they are in de
Lemur [1.5K]
You could assign values to variables and break it up into if else-if else statements.

<span>Pseudocode:</span>

if a < b and b < c:
    print("increasing")

else if a > b and b > c:
    print("decreasing")

else:
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Hope this helps.
7 0
3 years ago
When the _____ logical operator is used to combine keywords, a search engine will retrieve all results containing either keyword
DanielleElmas [232]
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8 0
3 years ago
Read 2 more answers
The Sleeping-Barber Problem:
s2008m [1.1K]

Answer:

Explanation:

Following are the Semaphores:

Customers: Counts waiting customers;

Barbers: Number of idle barbers (0 or 1)

mutex: Used for mutual exclusion.

Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves

Shared data variable:

count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.

// shared data

semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;

int count_cust= 0;

void barber() {

while(true) { //shop is always open

wait(customers); //sleep when there are no waiting customers

wait(mutex); //mutex for accessing customers1

count_cust= count_cust-1; //customer left

signal(barbers);

signal(mutex);

cut_hair();

}

}

void customer() {

wait(mutex); //mutex for accessing count_cust

if (count_cust< n) {

count_cust= count_cust+1; //new customer

signal(customers); signal(mutex);

wait(barbers); //wait for available barbers get_haircut();

}

else { //do nothing (leave) when all chairs are used. signal(mutex);

}

}

cut_hair(){ waiting(cutting);

}

get_haircut(){

get hair cut for some time; signal(cutting);

}

6 0
3 years ago
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