How do I solve this inequality?

Identify which of the following questions

slava [35]

Answer:

a and e I believe

Step-by-step explanation:

this is because to answer those questions you need to survey multiple different people, you'd need more than just an answer if you were to find the average of something. For the other questions they're very direct and only have one answer. Therefore you wouldnt need a statistical process for the other questions and only for a and e.

5 0

3 years ago

Y = x2 + 2x - 8<br><br> What is domain

Ksju [112]

Answer:

Step-by-step explanation: The domain of the expression is all real numbers except where the expression is undefined

5 0

2 years ago

If 25% of y is 30, what is 60% of y?

madam [21]

Answer:

60% of Y is 72

Step-by-step explanation:

25% of Y is 30 so multiply 30 by 4 and you get 120. Multiply 120 by .60 and that leaves you with 72 as your answer.

5 0

3 years ago

In proof testing of circuit boards, the probability that any particular diode will fail is . Suppose a circuit board contains di

ira [324]

Complete Question

In proof testing of circuit boards, the probability that any particular diode will fail is 0.01.

Suppose a circuit board contains 200 diodes. How many diodes would you expect to fail, and what is the standard deviation of the number that are expected to fail? What is the (approximate) probability that at least four diodes will fail on a randomly selected board?If five boards are shipped to a particular customer, how likely is it that at least four of them will work properly? (A board works properly only if all its diodes work)

Answer:

The number of diode expected to fail is

$\mu =2$

The standard deviation is

$\sigma = 1.407$

The probability that at least four diodes will fail on a randomly selected board is

$P(X \ge 4) = 0.1419$

Step-by-step explanation:

Generally the testing follows a binomial distribution because

1 The number of trials is finite

2 There is only two outcomes( which (a) A diode fail (b) a diode does not fail)

3 The each individual trial is independent of each other.

4 The chances of success is constant for every trial

From the question we are told that

The probability that a diode will fail is $p = 0.01$

The sample size is n = 200

Generally the number of diode expected to fail is mathematically represented as

$\mu = n * p$

=> $\mu = 200 * 0.01$

=> $\mu =2$

Generally the standard deviation is mathematically represented as

$\sigma = \sqrt{ np * (1 - p)}$

=> $\sigma = \sqrt{ 200* 0.01 * (1 - 0.01 )}$

=> $\sigma = 1.407$

Generally the probability that at least 4 diode will fail is mathematically represented as

$P(X \ge 4) = 1 - P(X < 4 )$

Generally

$P(X < 4 ) = P(X = 0 ) + P(X = 1) + P(X = 2) + P(X = 3)$

=> $P(X < 4 ) = ^nC_0 p^0 * (1-p)^{n-0} +^nC_1 p^1 * (1-p)^{n-1}+^nC_2 p^2 * (1-p)^{n-2}+ ^nC_3 p^3 * (1-p)^{n-3}$

=> $P(X < 4 ) = ^{200}C_0 p^0 * (1-0.01)^{200-0} +^{200}C_1 (0.01)^1 * (1-0.01)^{200-1}+^{200}C_2 (0.01)^2 * (1-0.01)^{200-2}+ ^{200}C_3 (0.01)^3 * (1-0.01)^{200-3}$