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Leya [2.2K]
2 years ago
15

How do I solve this inequality?

Mathematics
1 answer:
ch4aika [34]2 years ago
7 0
The correct answer is: x ≥1
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How many real roots and how many complex roots exist for the polynomial
Volgvan

Answer:

D. 4 real roots and 0 complex roots

Step-by-step explanation:

If I assume that the function you are saying is

F(x)=x^4+x^3-5x^2+x-6

There should be up to "4 roots," there can't be more or less than 4 total solutions. First, we need to check how many sign changes are there in this function. There are 3 positive real roots. Now lets check for negative roots.

F(-x)=x^4-x^3-5x^2-x-6

There are is only 1 negative real root. Since we basically have 4 real roots, and the max is 4. There should be 4 real roots and 0 complex roots.

8 0
3 years ago
4 - (-8) =<br> What is the answer
lianna [129]

Answer:

12

Step-by-step explanation:

When you subtract a negative number, the two negatives make a plus sign.

4 - (-8)

= 4 + 8

= 12

5 0
3 years ago
Please I need this before 12pm
luda_lava [24]

Answer:

The required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Step-by-step explanation:

The total number of squares of the the first term = 4

The total number of squares of the the second term = 7

The total number of squares of the the third term = 10

so,

a_1=4

a_2=7

a_3=10

Finding the common difference d

d=a_3-a_2=10-7=3

d=a_2-a_1=7-4=3

As the common difference 'd' is same, it means the sequence is in arithmetic.

So

If the initial term of an arithmetic progression is {\displaystyle a_{1}} and the common difference of successive members is d, then the nth term of the sequence (a_n) is given by:

                         {\displaystyle \ a_{n}=a_{1}+(n-1)d}

Therefore, the required formula is:

                                                          {\displaystyle \ a_{n}=a_{1}+(n-1)d}

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3 years ago
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