3 years ago

TIME

Mathematics

1 answer:

NISA [10]3 years ago

8 0

I’m not going to text him but I told my mom she was fine but she told her that I told my dad

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The equation x^2/121 + y^2/1. what points are the vertices of the eclipse

Alla [95]

Answer:

$(-11,0)$ and $(11,0)$ .

Step-by-step explanation:

The given ellipse has the equation:

$\frac{x^2}{121}+\frac{y^2}{1}=1$

This can be rewritten as

$\frac{x^2}{11^2}+\frac{y^2}{1^2}=1$

We compare this to the general equation of the ellipse:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

We have $a=11$ and $b=1$

The vertices of this ellipse are at $(-a,0)$ and $(+a,0)$ .

Therefore the vertices of this ellipse are at $(-11,0)$ and $(11,0)$ .

The correct choice is A.

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3 years ago

CAN SOMEONE ANSWER THIS!!!!!!!!!!

hammer [34]

2/x + 9
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3 years ago

12(6k+3)+4(7-5k) the distributive property simply each expression

hodyreva [135]

The distributive property: a(b + c) = ab + ac

12(6k + 3) + 4(7 - 5k) = 12(6k) + 12(3) + 4(7) + 4(-5k)

= 72k + 36 + 28 - 20k = 52k + 64

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3 years ago

Solve y+2x=5;x=-1,0,3

Anni [7]

If x=-1 => y-2=5=> y=7,x=-1
If x=0=> y+0=5=> y=5,x=0
If x=3=> y+6=5=> y=-1,x=3

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4 years ago

Which of the following measurements could be the side lengths of a right triangle?

n200080 [17]

I think the answer would be d

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