Question

The equation x^2/121 + y^2/1. what points are the vertices of the eclipse

Answer 1

Answer:

$(-11,0)$ and $(11,0)$.

Step-by-step explanation:

The given ellipse has the equation:

$\frac{x^2}{121}+\frac{y^2}{1}=1$

This can be rewritten as

$\frac{x^2}{11^2}+\frac{y^2}{1^2}=1$

We compare this to the general equation of the ellipse:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$

We have $a=11$ and $b=1$

The vertices of this ellipse are at $(-a,0)$ and $(+a,0)$.

Therefore the vertices of this ellipse are at $(-11,0)$ and $(11,0)$.

The correct choice is A.