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Komok [63]
3 years ago
13

1. Solve -21 < -3x + 6 < 12

Mathematics
1 answer:
guapka [62]3 years ago
5 0

Answer:

-2<x<9

Step-by-step explanation:

−21<−3x+6<12-21<-3x+6<12

Move all terms not containing xx from the center section of the inequality.

Tap for more steps...

−27<−3x<6-27<-3x<6

Divide each term in the inequality by −3-3.

−27−3>−3x−3>6−3-27-3>-3x-3>6-3

Divide −27-27 by −3-3.

9>−3x−3>6−39>-3x-3>6-3

Cancel the common factor of −3-3.

Tap for more steps...

9>x>6−39>x>6-3

Divide 66 by −3-3.

9>x>−29>x>-2

Rewrite the interval so that the left value is less than the right value. This is the correct way to write an interval solution.

−2<x<9-2<x<9

The result can be shown in multiple forms.

Inequality Form:

−2<x<9-2<x<9

Interval Notation:

(−2,9)

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Answer:

isosceles: 2 angles are the same and 2 sides are the same. Equilateral have all the same sides and angles. Saclene have all dfferent angles and sides.

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Write and equation of the line that passes through the pair of points (4,6) and (-1,1)
bazaltina [42]

Answer:

y = x + 2

Step-by-step explanation:

Step 1: Find the slope

m=\frac{y2-y1}{x2-x1} = \frac{6-1}{4-(-1)}=\frac{6}{6} =1

Step 2: Substitute the slope and a point in to find y intercept

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What is the sum of the arithmetic series 18 sigma t-1 (5t-4)?
just olya [345]

Answer:

783

Step-by-step explanation:

We have to find the sum of Arithmetic series from t = 1 to t = 18 represented by (5t - 4)

The formula to find the sum of an Arithmetic series when first and the last term is known is:

S_{n}=\frac{n}{2}(a_{1}+a_{n})

Here,

n = Total number of terms = 18

a_{1} = First Term = 5(1) - 4 = 1

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Using the values in the above formula, we get:

S_{18}=\frac{18}{2}(1+86)\\\\ S_{18}=9(87)\\\\ S_{18}=783

Thus, the sum of 18 terms of the given Arithmetic Series is 783.

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