3 years ago

00:00

Mathematics

1 answer:

Nady [450]3 years ago

8 0

Answer:

no,yes,no,yes

Step-by-step explanation:

if you wanna check if a relation is function or not , you can simply check if you have more than one x with same y.for example : for the first relation, you have (2,5) and (2,7) . so this isnt a function

You might be interested in

Write the two statements that create the biconditional: There is traffic on the freeway if and only if there are a lot of cars o

MariettaO [177]

Answer:

there is traffic on the freeway

a lot of cars on the freeway

Step-by-step explanation:

5 0

3 years ago

Please I really need help with this

Delvig [45]

Answer:

Step-by-step explanation:

㏒ 3+㏒(x+2)=1

㏒3(x+2)=1

3(x+2)=10^1

3x+6=10

3x=10-6=4

x=4/3

so A

$log_{2}x+log_{2}(x+2)=3\\or~log_{2}[x(x+2)]=3\\x(x+2)=2^3\\x^2+2x-8=0\\x^2+4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x+4)(x-2)=0\\x=2,-4\\x=-4 ~is~an~extraneous~solution.\\B$