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![We \ first, \ simplify \ \frac{125}{2} \\ \\ \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\ pulling \ out \ like \ factors : \\ \\ 2x^3 - 125x = x * (2x^2 - 125) \\ \\ Factoring: \ 2x^2 - 125](https://tex.z-dn.net/?f=We%20%5C%20first%2C%20%5C%20simplify%20%5C%20%20%5Cfrac%7B125%7D%7B2%7D%20%5C%5C%20%5C%5C%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%28%28x%5E3%29-%28%20%5Cfrac%7B125%7D%7B2%7D%2Ax%29%29-10%20%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%5Cboxed%7Bx%5E3%3D%20%5Cfrac%7Bx%5E3%7D%7B1%7D%20%3D%20%5Cfrac%7Bx%5E3%2A2%7D%7B2%7D%20%7D%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cboxed%7B%20%5Cfrac%7Bx%5E3%2A2-%28125x%29%7D%7B2%7D%20%3D%20%5Cfrac%7B2x%5E3-125x%7D%7B2%7D%20%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cfrac%7B%282%5E3-125x%7D%7B2%7D%20-10%20%5C%5C%20%5C%5C%20%20pulling%20%5C%20out%20%5C%20like%20%5C%20factors%20%3A%20%5C%5C%20%5C%5C%20%202x%5E3%20-%20125x%20%20%3D%20%20%20x%20%2A%20%282x%5E2%20-%20125%29%20%5C%5C%20%5C%5C%20Factoring%3A%20%5C%20%202x%5E2%20-%20125%20)
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Here's how!</span>

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Therefore</span>
. . .

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The factors would then be the following:</span>
→

→

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

<span>✔</span>