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Masja [62]
3 years ago
13

Web design and development tools

Computers and Technology
1 answer:
Rama09 [41]3 years ago
6 0

Answer:

Explanation:

Atom. Atom is relatively a new kid on the block of code editors. ...

Sublime Text. The Sublime is among the most popular text code editors out there. ...

Notepad++ Notepad++ is a powerful open source text editor, which only works on Windows. ...

Vim. ...

Visual Code Studio. ...

Django. ...

Ruby On Rails. ...

Angular.

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Alex Ar [27]

Answer: Incomplete question

Explanation: The question attached is incomplete and incoherent, possible solution of this will be difficult to assume. Take adequate time to post complete questions.

Regards.

4 0
3 years ago
You can easily merge files even if each file contains a different record layout. Group of answer choices True False
pychu [463]

Answer:

true!! i may be wrong tho

Explanation:

7 0
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Consider the following C code fragment:
wlad13 [49]

Answer:

10

Explanation:

Pointer arithmetic is tricky. The address is incremented by the sizeof the pointed element. A short is 2 bytes.

So adding 10 adds 20 bytes to the starting address of arr[].

In the expression, you're adding 10-6 = 4 to the start of the array, so you're pointing at the fifth element, arr[4] which is 10.

8 0
3 years ago
Write a routine to interchange the mth and nth elements of a singly-linked list. You may assume that the ranks m and n are passe
IRINA_888 [86]

Answer:

//The routine to swap m th and nth ranked elements

void swapmAndn(int m, int n)

{

  //Set the linked list head node

  Linked_Node **node_head

  //To find the m ranked node

  //set previous node  

  Linked_Node *node_prev = NULL;

 

  //set node to store m ranked node as head node

  Linked_Node *node_current_m = *node_head;

 

  //set the rank as rm=1

  rm =1

  //traverse to find the m ranked node

  while (node_current_m && rm<m)

  {    

      node_prev = node_current_m;

      node_current_m = node_current_m->next;

      rm++;

  }

 

  //To find the n ranked node

  //set previous node  

  Linked_Node *node_prev_n = NULL;

 

  //set node to store n ranked node as head node

  Linked_Node *node_current_n = *node_head;

 

  //set the rank as rn=1

  rn =1

  //traverse to find the n ranked node

  while (node_current_n && rn<n)

  {    

      node_prev_n= node_current_n;

      node_current_n = node_current_n->next;

      rn++;

  }

 

  //if m is not first ranked node

  if (node_prev != NULL)

      //set node_current_n as previous node

      node_prev->next = node_current_n;

 

  //otherwise Set the node_current_n

  else

      *node_head = node_current_n;

 

  // If n is not first ranked node

  if (node_prev_n!= NULL)

      node_prev_n->next = node_current_m;

  else

      *node_head = node_current_m;

 

  //now swap the next pointers also

  //to make the swap process complete  

  Linked_Node *temp = node_current_n->next;

  node_current_n->next = node_current_m->next;

  node_current_m->next = temp;

}

Explanation:

3 0
3 years ago
True or false The List interface defines a collection for storing elements in a sequential order.
Veseljchak [2.6K]

Answer:

True

Explanation:

A list is a collection where the elements are stored in the ordered sequence and it allows access to each of he elements by its position in the sequence. It allows duplicate values to be stored. It also allows insertion of elements and positional access.

A list is one of the three major categories of the Java collections. The other two categories are maps ans sets.

4 0
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