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Inessa [10]
3 years ago
5

Why is it important to have regular maintenance and care of your office equipment?

Computers and Technology
1 answer:
mr Goodwill [35]3 years ago
3 0
It is important to have regular maintenance on office equipment because by having regular maintenance they would be able to determine if a problem is about to occur on the office equipment before it puts the equipment out of commission. This would save money for the office because they would be able to fix the problem cheaper than buying new equipment.
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If someone you don’t know asks where you go to school, what should you do
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Answer:

Don't answer him because you don't know what he is going to do

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Print settings

author off document

how many times it has been viewed

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Read 2 more answers
A drink costs 3 dollars. A pizza costs 6 dollars. Given the number of each, compute total cost and assign to totalCost. Ex: 2 dr
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5 0
2 years ago
Visual Basics: 1 ) Write an if/else statement that compares the double variable pH with 7.0 and makes the following assignments
Lemur [1.5K]

Answer:

visual basic: 1)

Module PHmodule

   Sub Main()

       'Creating a variable for each entity

       dim ph as double = 0.0, neutral,base,acid as boolean

       'Writing a line to show user what to do

       console.writeline("Enter the pH :")

       'Taking the value

       ph=console.readline()

       'using if & elseif statement for distingushing the values into correct catagories

       if ph<7.0 then

       neutral=false:base=false:acid=true

       elseif ph>7.0 then  

       neutral=false:base=true:acid=false

       elseif ph=7.0 then

       neutral=true:base=false:acid=false

       end if

       'Printing the result

       console.writeline(" Neutral :" & Neutral)

       console.writeline(" base :" & base)

       console.writeline(" acid :" & acid)

       'command for staying in the command prompt for reading the result

       console.readline()

   End Sub

End Module

visual basic: 2)

Module AGEmodule()

  Sub Main()

       'Creating a variable for each entity

       dim age,minors,adults,seniors as integer = 0

       'Taking age from user

       console.writeline("Enter the age")

       age=console.readline()

       'using if & elseif statement for checking the age differnce

       if age<18 then'

       minors +=1

       else if age>18 and age<64 then

       adults +=1

       else if age>64 then  

       seniors +=1

       end if

       'printing result

       console.writeline("minors="&minors)

       console.writeline("adults="&adults)

       console.writeline("seniors="&seniors)

       'command for reading the result  

       console.readline()

  End Sub

End Module

Explanation:

visual basic 1) it is very simple program which allow us to find if the substance is acidic, basic or neutral. we use sim statement for making a variable as double (gives value in decimal) which allow to take a value from the user through console.readline() command and then by using the if statement we apply the condition if the ph is less then, greator then or equal to 7.0 value. thus the program gives us the answer. console.writeline() command is used to print a command on the screen while console.readline() command let us read the lines until we press enter.

visual basic 2)a program which allow us to count and add number of persons according to their age. we use dim statement for creating the variable as integers in which we take the age from user and then after checking it through if statement we increment according to three categories i.e. minors, adults, seniors. the console.writeline() command allow us to print anything on screen and console.readline() allowus to take value while compiling.

thank you...

6 0
3 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
2 years ago
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