I’m pretty sure you set the perimeters equal to each other, it would look like 3x+8+3x+7+3x = 3x+3x+4x+2 and then you add the similar ones so it would look like 9x+15 = 10x+2 then you subtract the two from both sides and subject the 9x from both sides and get 13 = x AB would be 47 BC = 46 AC = 39 PQ = 39 QR = 39 PR = 54 then you could double check 47+46+39 = 39+39+54 132 = 132