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2<br> Write the ratio 2kg: 500g in its simplest form

sammy [17]

Answer:

1kg:250g

Step-by-step explanation:

2kg:500g

dividing both sides by 2, we get

1kg:250g

4 0

3 years ago

Answer this correctly for brainliest pls!!

Molodets [167]

A function that depicts depreciation can be represented as equations, graphs and tables.

<h3>The yearly value of each car for the first five years</h3>

The functions are given as:

$V(t) =C(1 - r^t)$

$V(t) =C(1 - r)^t$

Where:

C = 5895 --- the initial value of the car

r = 22% --- the rate of depreciation

For the first 5 years, the values of t = 1, 2, 3, 4 and 5

For the first function, we have:

$V(1) =5895(1 - 22\%^1) = 4598.1$

$V(2) =5895(1 - 22\%^2) = 5609.7$

$V(3) =5895(1 - 22\%^3) = 5832.2$

$V(4) =5895(1 - 22\%^4) = 5881.2$

$V(5) =5895(1 - 22\%^5) = 5892.0$

For the second function, we have

$V(1) =5895(1 - 22\%)^1 = 4598.1$

$V(2) =5895(1 - 22\%)^2 = 3586.5$

$V(3) =5895(1 - 22\%)^3 = 2797.5$

$V(4) =5895(1 - 22\%)^4 =2182.0$

$V(5) =5895(1 - 22\%)^5 = 1702.0$

So, the table of values is:

$\left[\begin{array}{ccc}Years&Car\ 1&Car\ 2\\1&4598.1&4598.1\\2&5609.7&3586.5\\3&5832.2&2797.5\\4&5881.2&2182.0\\5&5892.0&1702.0\end{array}\right]$

See attachment for the graphs of the two functions

<h3>Interpreting the graphs</h3>

The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.

This means that, the graph 2 that follows an exponential pattern is more realistic

<h3>The worth of the cars after 5 years</h3>

From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0

Read more about graphs and functions at:

brainly.com/question/13473114

5 0

2 years ago

A bag contains 4 red marbles, 8 blue marbles and 2 green marbles. If two marbles are drawn out of the bag, what is the exact pro

navik [9.2K]

Well if you add all the numbers together, the total is 14. So 4/14 chance of pulling out a red marble.

7 0

3 years ago

I need help with Multiplication Properties of Exponents desperately!! I've tried to solve both problems repeatedly and I cannot

Yuliya22 [10]

Answer:

1) x= -36.

2) x = 0.

Step-by-step explanation:

1) Taking the 3rd power to both sides and using the following exponent law:

$\left(a^b\right)^c = a^{bc}$

we get:

$\left(\left(m^{x}\right)^{\frac{1}{3}}\right)^3 = \left(m^{-12}\right)^3 \\ m^x = m^{-36}$

So this tells us that x = -36.

2) We can distribute the power inside every term. So the left side becomes:

$\left(3x^3y^x\right)^3 = 3^3\left(x^3)^3y^{3x} = 27x^9y^{3x}$

Now, the trick here is to remember that $y^0 = 1$ , so replacing 1 with $y^0$ , which then gives us:

$27x^9y^{3x} = 27x^9y^{0}$ , telling us that 3x = 0 and thus, x = 0.

7 0

4 years ago

Karrine hit 4 more home runs than half the number of home runs Lu hit. Together they hit 10 home runs. Let x represent the numbe

Andreas93 [3]

Answer:

The number of home runs that Lu hit is 4 and the number of home runs that Karrine hit is 6

Step-by-step explanation:

Let

x ----> represent the number of home runs Lu hit

y ---> represent the number of home runs Karrine hit

we know that

Together they hit 10 home runs

so

$x+y=10$ ----> equation A

Karrine hit 4 more home runs than half the number of home runs Lu hit

so

$y=\frac{1}{2}x+4$ ---> equation B

substitute equation B in equation A

$x+\frac{1}{2}x+4=10$

solve for x

$\frac{3}{2}x=10-4$

$\frac{3}{2}x=6\\x=4$

Find the value of y

$y=\frac{1}{2}(4)+4=6$

therefore

The number of home runs that Lu hit is 4 and the number of home runs that Karrine hit is 6

5 0

3 years ago