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Ludmilka [50]
3 years ago
14

The North Star is approximately 4,085 trillion kilometers away from earth. If 1 light

Mathematics
1 answer:
kumpel [21]3 years ago
6 0

Answer:

I don't get the question meaning

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Determine the points of intersection of the line y=2x+5 and the circle x²+y²=36
Vladimir79 [104]

The two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

<h3>How to find the points of intersection?</h3>

Here we want to solve the system of equations:

y = 2x + 5

x² + y² = 36

To solve this, we need to replace the first equation into the second one:

x² + (2x + 5)² = 36

Now we can solve this for x:

x² + 4x² + 10x + 25 = 36

5x² + 10x - 11 = 0

This is a quadratic equation, to solve it we use the general formula:

x = \frac{-10 \pm \sqrt{10^2 - 4*5*(-11)} }{2*5} \\\\x = \frac{-10 \pm 17.9 }{10}

So we have two solutions for x:

x = (-10 - 17.9)/10 = -2.79

x = (-10 + 17.9)/10 = 0.79

To get the y-values of the solutions, we evaluate the linear equation in these values of x:

y = 2*(-2.79) + 5 = -0.58

y = 2*( 0.79) + 5 = 6.58

Then the two intersection points are (-2.79,  -0.58) and (0.79,  6.58).

If you want to learn more about intersection points:

brainly.com/question/17206319

#SPJ1

5 0
2 years ago
What is one of the best methods to multiply these binomials: (x+8)(x+7)
Elodia [21]
The answer is C, you can do this by doing FOIL
3 0
2 years ago
Read 2 more answers
Math question:
nignag [31]

Answer: 352

Step-by-step explanation:

3 0
2 years ago
Please help with the following question
Alex17521 [72]
P1=(0,0)=(x1,y1)→x1=0, y1=0
P2=(3,-2)=(x2,y2)→x2=3, y2=-2

Slope: m=(y2-y1)/(x2-x1)
m=(-2-0)/(3-0)
m=(-2)/3
m=-2/3

Point-slope equation:
y-y1=m(x-x1)
y-0=(-2/3)(x-0)
y=-(2/3)x

Answer: The equation of the line is: y=-(2/3)x
5 0
3 years ago
Quadrilateral abcd is a rhombus and points c, d, and e are on the same line. is quadrilateral abde a rhombus?
Step2247 [10]
No, because BC and BD are not the same lengths. If AB = BC, then AB and BD are not the same lengths -> ABDE is not a rhombus.
6 0
2 years ago
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