Find the ordered pair $(s,t)$ that satisfies the system
1 answer:
Answer:
Step-by-step explanation:
The given system of equations is presented as follows;
3·t - 6·s = 9
Making <em>t</em> the subject of both equations, gives;
In the first equation; t = (3 - s/2)/5
In the second equation; t = (9 + 6·s)/3
Equating both values of <em>t</em> to find the the values that satisfies both equations, gives;
(3 - s/2)/5 = (9 + 6·s)/3
3 × (3 - s/2) = 5 × (9 + 6·s)
9 - (3/2)·s = 45 + 30·s
45 - 9 = (30 + (3/2))·s
36 = (63/2)·s
s = 36/(63/2) = 8/7
t = (3 - s/2)/5
∴ t = (3 - (8/7)/2)/5 = 17/35
Therefore, the ordered pair is (8/7, 17/35)
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The hurdle and runner form a right triangle (see attached picture) such that
sin(30°) = <em>h</em> / (5 ft)
and
cos(30°) = <em>x</em> / (5 ft)
where <em>h</em> is the height of the hurdle and <em>x</em> is the horizontal distance from where the runner jumps to the hurdle. So
<em>h</em> = (5 ft) sin(30°) = 5/2 ft = 2.5 ft
<em>x</em> = (5 ft) cos(30°) = (5√3)/2 ft ≈ 4.33 ft
