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julia-pushkina [17]
3 years ago
13

Find the ordered pair $(s,t)$ that satisfies the system

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

\left(\dfrac{8}{7} , \ \dfrac{17}{35} \right)

Step-by-step explanation:

The given system of equations is presented as follows;

\dfrac{s}{2} + 5 \cdot t = 3

3·t - 6·s = 9

Making <em>t</em> the subject of both equations, gives;

In the first equation; t = (3 - s/2)/5

In the second equation; t = (9 + 6·s)/3

Equating both values of <em>t</em> to find the the values that satisfies both equations, gives;

(3 - s/2)/5 = (9 + 6·s)/3

3 × (3 - s/2) = 5 × (9 + 6·s)

9 - (3/2)·s = 45 + 30·s

45 - 9 = (30 + (3/2))·s

36 = (63/2)·s

s = 36/(63/2) = 8/7

t = (3 - s/2)/5

∴ t = (3 - (8/7)/2)/5 = 17/35

Therefore, the ordered pair is (8/7, 17/35)

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Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

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so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

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