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worty [1.4K]
3 years ago
7

Which list contains only composite numbers?

Mathematics
2 answers:
aev [14]3 years ago
7 0

Answer:

A

Step-by-step explanation:

bc it is E jk A

Maksim231197 [3]3 years ago
3 0

Answer: A composite number can be divided into a whole number other than itself and one. A prime number can only be divided by itself and one.

Step-by-step explanation: Ex: 1,2,3,5,7,11,13, etc are prime. 4,6,8,9, etc are composite numbers. So... the first list is correct because 6 (3*2), 24(6*4), 51 (3*17), 105 (5*21) can all be multiplied by integers other than itself and one.

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P = 215(1.005)t/3
Reil [10]

Answer:

(D) 36

Step-by-step explanation:

0.5%  = 0.5/100  =  0.005

It is given that the population (215) is predicted to increase by 0.5%. To know the value after increment, 215 has to be multiplied by (1 + 0.005) or 1.005.

In the equation P  =  215(1.005)t/3, the value of t/3 has to be equal to 1 for 0.5% increase.

t/3  =  1

t  =  3 years

Convert years to months.

n  =  3 ⋅ 12 months

n  =  36 months

The correct option is D.

Thanks!

Mark me brainliest!

6 0
2 years ago
Given the function f(x) = 3x3 + 7x2 + 5x, find f(-3).
Julli [10]

Answer:

the ans is b -33

Step-by-step explanation:

by putting the -3 in the place of x and adding,subtracting

4 0
3 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
2 years ago
ANSWER PLZ QUICK AND FAST
stich3 [128]
Subtract 9 from both sides
7 0
3 years ago
Read 2 more answers
Which inequality shows the situation?<br> Mary's elevation is more than - 10 feet.
tatuchka [14]

Answer:

first option e > -10

5 0
3 years ago
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