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xxTIMURxx [149]
3 years ago
7

Is the last question correct? (Last question is in first pic)

Mathematics
1 answer:
Vikentia [17]3 years ago
4 0

Answer:

If (K + 1)^2 = 2n + (n^2)/2, then the answer is Yes, else No.

Step-by-step explanation:

Sum of first K + 1 odd numbers (S): 1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1).

(1 + 3 + 5 + ... + (2K - 3) + (2K - 1) + (2K + 1)) + ((2K + 1) + (2K - 1) + (2K - 3) + ... + 5 + 3 + 1 ) = (2K + 2) + (2K + 2) + (2K + 2) + ... + (2K + 2) + (2K + 2) + (2K + 2) (repeat K + 1 times) = (2K + 2)(K + 1) = 2S

2S = (2K + 2)(K + 1)

S = (2K + 2)(K + 1)/2

S = (2K^2 + 4K + 2)/2

S = K^2 + 2K + 1

S = (K + 1)^2

(4n + n^2)/2 = 2n + (n^2)/2

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