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2 years ago

If the endpoints of AB are located at (0,7) and (8,8) what is the length of AB?

Mathematics

1 answer:

Leokris [45]2 years ago

5 0

Answer:

√65

Step-by-step explanation:

The distance formula can be represented as

$\sqrt{(x_{2} -x_1)^2 + (y_2-y_1)^2}$

Taking (8,8) as (x₂, y₂) and (0,7) as (x₁, y₁), we have

$\sqrt{(8 -0)^2 + (8-7)^2}\\= \sqrt{8^2 + 1^2}\\= \sqrt{65}$

as our answer

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$s=\sqrt[ ]{\frac{1}{N-1} \sum_{i=1}^{N}(x_{i}-{\displaystyle \textstyle {\bar {x}}}) ^{2} }$

Where:

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Let's start calculating the mean value:

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$s=\sqrt[ ]{\frac{1}{15-1}*(2173160)}$

$s=\sqrt[ ]{\frac{2173160}{14}}$

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