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3 years ago

14

In which expression should the exponents be multiplied?

1 answer:

gulaghasi [49]3 years ago

8 0

If we have the same base, we can do this:
(1/3)^4*(1/3)*7 = (1/3)^(4+7) = (1/3)^11
3^7/3^15 = (3^7)*(3*(-15)) = 3^(7 + (-15)) = 3^(-8) = 1/(3^8)
4^5*4^2 = 4^(5+2) = 4^7

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Please help me I’m really stuck

dalvyx [7]

Answer:

<u>/</u><u> </u>3=<u>/</u><u> </u>5 { alternate anglea}

<u>/</u><u> </u>5+<u>/</u>6 =180° {straight angle}

<u>/</u><u> </u>6=180-26

<u>/</u><u> </u>6=154°

hope it helps

<h3>stay safe healthy and happy.</h3>

6 0

3 years ago

Janey's height from age 7 to 12 can be modeled by the function h(t)=45+8/5t, where h(t) is Janey's height in inches and t is tim

aliina [53]

Write the ratio as a fraction in the fourth column of the table.

6 0

3 years ago

10090 7 Each railroad car in a train set is 6 inches in length. The railroad track is 5 feet long. How many railroad cars can it

Orlov [11]

Step-by-step explanation:
Given,
Length of railroad car = 6 inches
The length of railroad track = 5 feet
We will convert this length into inches.
1 feet = 12 inches
5 feet = 12*5 = 60 inches
Let,
x be the number of cars.
Number of cars * Length of each car = Length of track

Dividing both sides by 6

10 cars can fit on railroad track.

8 0

3 years ago

Read 2 more answers

The probability that a randomly selected 2 2-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0

Mnenie [13.5K]

Answer:

a. $Probability = 0.97735$

b. $Probability = 0.92294$

c. $P(At\ Least\ One) = 1$

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

$P(Live) = 0.98861$

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

$Probability = P(Live)\ and\ P(Live)$

$Probability = 0.98861 * 0.98861$

$Probability = 0.9773497321$

$Probability = 0.97735$ <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

$Probability = P(Live)^n$

Where $n = 7$

$Probability = 0.98861^7$

$Probability = 0.92294324145$

$Probability = 0.92294$ <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

$P(At\ Least\ One) = 1 - P(None).$

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

$P(Not\ Live) = 0.01139$

The probability that none of the 7 lives up to 3 is:

$P(None) = P(Not\ Live)^7$

$P(None) = 0.01139^7$

Substitute this value for P(None) in

$P(At\ Least\ One) = 1 - P(None).$

$P(At\ Least\ One) = 1 - 0.01139^7$

$P(At\ Least\ One) = 0.99999999999997513055642436060443621$

$P(At\ Least\ One) = 1$ ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0

3 years ago

An equilateral triangle has a height of 32. Find the length of the sides of the triangle. Round to the nearest hundredth.

telo118 [61]

Let each side=x
Use pythagorus
As height at mid of other side
Then: 32=sqrt(X^2-X^2/4)
Therefore X=36.950

5 0

2 years ago