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Simora [160]
4 years ago
14

In which expression should the exponents be multiplied?

Mathematics
1 answer:
gulaghasi [49]4 years ago
8 0
If we have the same base, we can do this:
(1/3)^4*(1/3)*7 = (1/3)^(4+7) = (1/3)^11
3^7/3^15 = (3^7)*(3*(-15)) = 3^(7 + (-15)) = 3^(-8) = 1/(3^8)
4^5*4^2 = 4^(5+2) = 4^7
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Clint has to spend a minimum of $75 in order to use his coupon at the store
Colt1911 [192]
Okay what’s the rest of the question ?
7 0
4 years ago
1E. The number 2A5A0A2 is divisible by 99. What is the digit A?
kirza4 [7]

Answer: A = 3

Step-by-step explanation:

The digit is 3. If A is 3, the number

2A5A0A2 becomes 2353032. We then divide by 99 and this will be:

= 2353032/99

= 23768

If we use 1, we'll have 2151012. Dividing by 99 gives:

= 2151012 / 99

= 21727.39

If we use 2, we'll have 2252022. Dividing by 99 gives:

= 2252022 / 99

= 22747.69

If we use 4, we will have 2454042. Dividing by 99 gives:

= 2454042 / 99

= 24788.30

If we use 5, we will have 2555052. Dividing by 99 gives:

= 2555052 / 99

= 25808.61

If we use 6, we will have 2656062. Dividing by 99 gives:

= 2656062 / 99

= 26828.91

If we use 7, we will have 2757072. Dividing by 99 gives:

= 2757072 / 99

= 27849.21

If we use 8, we will have 2858082. Dividing by 99 gives:

= 2858082 / 99

= 28869.52

If we use 9, we will have 2959092. Dividing by 99 gives:

= 2959092 / 99

= 29889.82

If we use 0, we will have 2050002. Dividing by 99 gives:

= 2050002 / 99

= 20707.09

Therefore, A is 3 as it gives 2353032 which divides 99 successfully without remainder.

5 0
3 years ago
Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
jarptica [38.1K]

Answer: IRT WOULD BE C bc likw look da chaer i dont gotta epsxlain

Step-by-step explanation:

6 0
3 years ago
Can some one hel me plz.
alekssr [168]
1.4,6,8
2.3,7,1 that how you get your answer
5 0
4 years ago
I can't seem to figure it out lol.​
fomenos

4y+2x+y+79-x=180°

5y+x=101

X=101 -5y

-------

3 0
3 years ago
Read 2 more answers
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