Answer:
Given : BRDG is a kite that is inscribed in a circle,
With BR = RD and BG = DG
To prove : RG is a diameter
Proof:
Since, RG is the major diagonal of the kite BRDG,
By the property of kite,
∠ RBG = ∠ RDG
Also, BRDG is a cyclic quadrilateral,
Therefore, By the property of cyclic quadrilateral,
∠ RBG + ∠ RDG = 180°
⇒ ∠ RBG + ∠ RBG = 180°
⇒ 2∠ RBG = 180°
⇒ ∠ RBG = 90°
⇒ ∠ RDG = 90°
Since, Angle subtended by a diameter or semicircle on any point of circle is right angle.
⇒ RG is the diameter of the circle.
Hence, proved.
Answer:
What is the equation?
Step-by-step explanation:
A straight line is 180°. So you can do:
(15x - 4) + (5x - 8) = 180 Simplify
20x - 12 = 180
20x = 192 Find the value of x
x = 9.6
m∠ABD = 15x - 4 Plug in x = 9.6
m∠ABD = 15(9.6) - 4 = 144 - 4 = 140°
m∠DBC = 5x - 8 Plug in 9.6
m∠DBC = 5(9.6) - 8 = 48 - 8 = 40°
Answer:
∠ HGL = 73°
Step-by-step explanation:
KL is a midsegment of the triangle and is parallel to HG, then
∠ KLJ = ∠ HGL ( corresponding angles ), so
9x - 62 = 5x - 2 ( subtract 5x from both sides )
4x - 62 = - 2 ( add 62 to both sides )
4x = 60 ( divide both sides by 4 )
x = 15
Thus
∠ HGL = 5x - 2 = 5(15) - 2 = 75 - 2 = 73°
