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umka2103 [35]
3 years ago
11

P(-2,5) and Q(3,2) are two points. Find the co-ordinates of the point R on PQ such that PR = 2QR.

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

R (1 1/3 , 3) or (1.333 , 3)

Step-by-step explanation:

R (x,y)

x = 3 - (3 - (-2))/3 = 3 - (5/3) = 3 - 1 2/3 = 1 1/3

y = 2 + (5-2)/3 = 2 + 1 = 3

R (1 1/3 , 3) or (1.333 , 3)

You might be interested in
What is the solution set of 14-3x <-1
Bond [772]

Answer:

-3x<-14-1

-3x<-15

x>5

5 0
3 years ago
Daniel and Sydney are getting high-speed Internet access at the same time. Daniel's provider charges $60 for installation and $4
Misha Larkins [42]

Answer:

5 months

Step-by-step explanation:

Daniel's provider charges $60 for installation and $45.95 per month. Sydney's provider has free installation and charges $57.95 per month

Let x = number of months

Daniel = 60 + 45.95x

Sydney = 0 + 57.95x

Equate both equations

60 + 45.95x = 0 + 57.95x

Collect like terms

60 - 0 =57.95x - 45.95x

60 = 12x

Divide both sides by 12

x = 60 / 12

= 5

x = 5 months

Daniel and Sydney would have paid the same amount for high-speed Internet service after 5 months

6 0
3 years ago
Is 2/3 greater than 2/5?
svetoff [14.1K]
Yes. 2/3 is greater than 2/5. You can check this by cross multiplication or easier just look at the denominator and numerator. In this case the numerator is the same so it's easier in a sense that you need to look at the denominator. Since the denominator 3 is close to the numerator 2 it shows that it's almost a whole unlike the other fraction. You can also convert each fraction to decimals and compare it which is also easy. Just divide the numerator by the denominator and you've got a decimal. Hope this helps!
7 0
4 years ago
Chipper had 189 hits in 572 at bats calculate chippers batting average for season by dividing the number if hits by the number o
lord [1]

Answer:

0.330

Step-by-step explanation:

Divide the number of hits (189) by the number of bats (572)

189/572=0.330

8 0
4 years ago
Kite EFGH is inscribed in a rectangle such that F and H are midpoints and EG is parallel to the side of the rectangle. Which sta
andrew11 [14]

Answer:

<h3>C.) The area of EFGH is always ¹/₂ of the area of the rectangle. </h3>

Step-by-step explanation:

If EG is parallel to the side of the rectangle then lenght of EG is equal to width of rectangle.

If F and H are midpoints of sides of rectangle then FH is parallel to the side of rectangle {wich is perpendicular to the side parallel to EG}. That means the lenght of FH is equal to lenght of rectangle, and FH is perpendicular to EG.

Then FH is sum of hights of triangles EFG and EHG (FH=H_{_{\Delta EFG}}+H_{_{\Delta EHG}}), and the area of EFGH is sum of areas of triangles EFG and EHG (A_{kite}=P_{_{\Delta EFG}}+P_{_{\Delta EHG}}).

So the area of the rectangle:  \bold{A_{rectangle}=EG\cdot FH}

The area of the kite:

                                  A_{kite}=P_{_{\Delta EFG}}+P_{_{\Delta EHG}}\\\\A_{kite}=\frac12 EG\cdot H_{_{\Delta EFG}}+\frac12 EG\cdot H_{_{\Delta EHG}}\\\\ A_{kite}=\frac12 EG\cdot (H_{_{\Delta EFG}}+H_{_{\Delta EHG}})\\\\A_{kite}=\frac12 EG\cdot FH\\\\A_{kite}=\frac12 A_{rectangle}

No matter the height of the triangles, so no matter the location of the EG

4 0
4 years ago
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