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Savatey [412]
2 years ago
6

WILL GIVE BRAINLIEST

Mathematics
1 answer:
lyudmila [28]2 years ago
7 0

Answer:

<h2>B. H, I, J</h2><h2>H(-5, -5), I(0, -6), J(2, -8)</h2>

Step-by-step explanation:

You have to draw sets:

y

in the coordinates system.

y=\dfrac{1}{2}x-1\\\\x=0\to y=\dfrac{1}{2}\cdot0-1=-1\to(0,\ -1)\\\\x=2\to y=\dfrac{1}{2}\cdot2-1=1-1=0\to(2,\ 0)

dashed line

mark the region below the line

y=-3x+2\\\\x=0\to y=-3\cdot0+2=2\to(0,\ 2)\\\\x=1\to y=-3\cdot1+2=-3+2=-1\to(1,\ -1)

solid line

mark the region below the line

Read points on the common region (look at the picture).

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Natalija [7]
2a.
Since BC = 10m and M is the midpoint, we can find CM by : 10÷2 = 5m
So, CM = 5m

2b. Now, you have the base ( 5m) & hypotenuse (13m). Pythagoras' Theorem:

c {}^{2}  =  {a}^{2}  +  {b}^{2}
Where c is the hypotenuse, a & b are sides.

{13}^{2}  =  {5}^{2}  + b {}^{2}  \\  {5}^{2}  +  {b}^{2}  = 13 {}^{2}  \\  {b}^{2}  = 13 {}^{2}  -  {5}^{2}  \\ b =  \sqrt{144}  \\ b = 12
b here refers to the height.

2c.
Area of a right-angled triangle =
\frac{base \times height}{2}
So,
\frac{10 \times 12}{2} \\  = 60 {m}^{2}
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