Write 5,020,700 in expanded form
2 answers:
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Answer:
C.4.18g
The amount will remain after 12 days is 4.18 g
Step-by-step explanation:
we can use formula
where
h is half life time
t is time in days
Po is initial quantity
P(t) is the quantity after t days
we are given
Curium-243 has a half-life of 28.5 days
In a sample of 5.6 grams of curium-243
so,
now, we can plug values
now, we can plug t=12
So,
The amount will remain after 12 days is 4.18 g