<span>Approximately 25.
Of the 5 grades of sand used in the United states, medium sand has particles ranging from 0.25 mm to 0.5 mm. For convenience, I'll use 0.5mm as the diameter of a grain of sand. Human cells range from a volume of 30 cubic micrometers (human sperm cell) up to 4 million micrometers (human egg cell). For the average human cell, I'll use an osteoblast with a volume of 4000 cubic micrometers or a diameter of 2x10^-5 meters.
Now just take the diameter of a grain of sand and divide by the diameter of a human cell.
5 x 10^-4 / 2x10^-5 = 5/2 x 10^(-4 - -5) = 2.5x10^1 = 25
So the diameter of a grain of sand at 0.5 mm is approximately 25 times larger than that of a human cell at 0.02mm</span>
Answer:5x7=35
8x5=40
Step-by-step explanation: well first think of what number can divide into 40 and 35 and come out as 5. So for example 35 divided 7 equals 5 and 40 divided 8 = 5 so the missing number is either 8 or 7
Answer:
D. Subtract 9y from both sides of the equation.
Step-by-step explanation:
A. Divide both sides of the equation by 36.
B. Multiply both sides of the equation by 6.
C. Add 9y to both sides of the equation.
D. Subtract 9y from both sides of the equation.
Given:
9y - 6x = 36
To solve for x
Step 1: subtract 9y from both sides
9y - 6x - 9y = 36 - 9y
- 6x = 36 - 9y
Step 2: Divide both sides by -6
- 6x / -6 = (36 - 9y) / - 6
x = (36 - 9y) / - 6
The answer is
x = (36 - 9y) / - 6
(3j, 3k) and (3/j, 3k)
So if their x values have the same signs and their y values have the same signs, they are in the same quadrant.
If j is negative, both 3j and 3/j would be negative. If j is positive then both 3j and 3/j are positive.
And 3k is the same as 3k.
Given: ∠A is a straight angle. ∠B is a straight angle.
We need to Prove: ∠A≅∠B.
We know straight angles are of measure 180°.
So, ∠A and <B both would be of 180°.
It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>
