URGENT!! PLEASE HELP!! What method could be used to prove the below triangles similar?

What is the difference between |-3|and -3?

Ber [7]

Answer:

c vbnnbvgh3456789okjhgc

Step-by-step explanation:

4 0

2 years ago

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What is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?

Alex787 [66]

Hi!
A is the answer:⏬⏬⏬⏬⏬⏬⏬⏬

The distance around a triangle, better noun as de "perimeter of a triangle"

is the total distance around the outside, which can be found by adding together the length of each side.

Perimeter (P) = Length A + Length B + Lenght C

In this case, we know that each side measure 2 \frac{1}{8}81 feet, 3 \frac{1}{2}21 feet, and 2 \frac{1}{2}21feet but we have to rewrite each one of this mixed fractions as improper fractions:

2 \frac{1}{8}81 = \frac{16 + 1}{8}816+1 = \frac{17}{8}817

3 \frac{1}{2}21 = \frac{6 + 1}{2}26+1 = \frac{7}{2}27

2 \frac{1}{2}21 = \frac{4 + 1}{2}24+1 = \frac{5}{2}25

Then we just add all of them to find the perimeter:

= \frac{17 + 28 + 20}{8}817+28+20 = \frac{65}{8}865

A: The distance around a triangle is \frac{65}{8}865feet

3 0

2 years ago

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Help plzz 2decimal places 165 x 0.38²

allsm [11]

Answer:

23.83

Step-by-step explanation:

3 0

2 years ago

Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10

Alenkasestr [34]

Answer: The correct option is (D) SET 4.

Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

Perpendicular² + Base² = Hypotenuse².

Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.

SET 1 : 14 cm, 5 cm, 6 cm.

We have

$5^2+6^2=25+36=61,\\\\14^2=196.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 2 : 8 in., 12 in., 20 in.

We have

$8^2+12^2=64+144=208,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 3 : 10 mm, 20 mm, 30 mm.

We have

$10^2+20^2=100+400=500,\\\\30^2=900.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 4 : 12 ft, 16 ft, 20 ft.

We have

$12^2+16^2=144+256=400,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² = Hypotenuse².

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0

3 years ago

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A 13-foot ladder is placed against a vertical wall of a building with the bottom of the ladder standing on level ground 7 feet f

NARA [144]

Answer:

64

Step-by-step explanation

8 times 8 is 64 just write that down

6 0

2 years ago