Answer:
A) 30
B) 12 kg
C) 2,125 m
Step-by-step explanation:
Hi there!
»»————- ★ ————-««
I believe your answer is:
31.69
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
- '9' is in the hundredths place. The rounding is the digit to it's right, or '3'.
- Since 3 is less than or equal to 4, we would round down.
⸻⸻⸻⸻
31.693 ≈ 31.69
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
Answer:
The required specific heat is 196.94 joule per kg per °C
Step-by-step explanation:
Given as :
The heat generated = Q = 85.87 J
Mass of substance (m)= 34.8 gram = 0.0348 kg
Change in temperature = T2 - T1 = 34.29°C - 21.76°C = 12.53°C
Let the specific heat = S
Now we know that
Heat = Mass × specific heat × change in temperature
Or, Q = msΔt
Or, 85.87 = (0.0348 kg ) × S × 12.53°C
Or , 85.87 = 0.4360 × S
Or, S = 
∴ S = 196.94 joule per kg per °C
Hence the required specific heat is 196.94 joule per kg per °C Answer
Answer:
35
Step-by-step explanation:
5 x 7 = 35
Answer:

Step-by-step explanation:
25= r•r•8 ⇔ 25/8 = r²
then
