<span>a. What is the probability that the printer produces more than 12,000 pages before this cartridge must be replaced?
solution
to solve the equation we need to find the z-score:
z=(x-</span>μ)/σ
where:
x=12000
μ=mean=11500
σ=standard deviation=800
thus
z=(12000-11500)/800=0.625
thus
P(x>12000)=1-P(x<12000)=1-0.7357=0.2643
<span>b. What is the probability that the printer produces fewer than 10,000 pages?
z=(10000-11500)/800
z=-1.875
hence
P(x<10000)
=0.0301
</span>
The period of the function is pi/b, b=2 and therefore the period is pi/2, half of that is the vertical asymptote which is positive or negative pi/4
A. .x -x=0
x+ -x=0
0=0
all real numbers are solutions
b. x-y+(-x)=x-y+(-x)
-y=-y
0=0
x=0/0 0 over 0
I believe the answer would be 4/6 which would simplify to 2/3
