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enyata [817]
3 years ago
12

PLEASE HELP!!!!!!!!!!!!!

Mathematics
1 answer:
Slav-nsk [51]3 years ago
8 0
9 square units.

the area of a triangle is 1/2 base x height.

the base of this triangle is the line RS which is 6 units long, and the height is the dashed line, which is 3 units long. 1/2 x 6 x 3 = 9
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The table shows the volume V (in cubic feet) of a cube with a side length of x feet. Does the table represent a linear or nonlin
Reika [66]

Answer:

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8 0
3 years ago
Brandon is thinking of a number that is divisible by 6 and 8 . What is the smallest number that Brandon could think of
a_sh-v [17]

since

6 = 2 * 3 <--- two factors


8 = 2 * 2 * 2 <--- three factors


and since the "2" is there on each, then we can just use that instance of it once.


so instead of using 2 * 3 * 2 * 2 * 2, we'll use 2 * 3 * 2 * 2, and that is our LCD.


2 * 3 * 2 * 2 = 24.

4 0
4 years ago
Sam rotated parallelogram ABCD 90° clockwise around the origin. If angle A is 130° and angle B is 50°, what is the degree measur
irakobra [83]

<u>Answer-</u>

The measurement of angle A' will be 130° .

<u>Solution-</u>

Transformations like - rotations, reflections, and translations are isometric.  That means that these transformations do not change the size of the figure.  If the size and shape of the figure is not changed, then the figures are congruent.

It doesn't matter the order or how much degree of rotation has taken place, the final image will be congruent to the original image.

So, even after the rotation of 90° clockwise around the origin, the measurement of angle A will be 130° and so do all the rest of the angles.



8 0
3 years ago
Read 2 more answers
Solve the triangle.<br><br> B = 36°, a = 38, c = 18
Lady_Fox [76]
Solving the triangle requires solving all of the dimensions involve in the polygon given. We are given an angle, and two of the sides of the triangle. We can solve the third side by using the law of cosines.

b² = a²+c²-2accos(B)
b² = 38² + 18² - 2(38)(18)cos(36)
b = 25.7

We use the law of sines to solve for the angles.
a/sinA = b/sinB
38/sinA = 25.7/sin36
A = 60.4
°
C =
180 - 36 - 60.4 = 83.6°
4 0
3 years ago
Divide the square root of 81 by the difference between the product of-1 and -3 and the square root of 4​
kherson [118]

Answer:  \frac{9}{1}

Step-by-step explanation:

FIrst find the square root of 81.

\sqrt{81}  = 9  

The square root of 81 is 9.

FInd the product of -1 and -3 by multiplying the -1 by -3.

-1 * -3 = 3

next find the square root of 4.

     

   \sqrt{4} = 2  

Now it said divide  the square root of 81 which is 9 by  the difference between 3 and 2 and the difference between 3 and 2 two is 1.  

Thos means that the answer will be 9/1.

7 0
3 years ago
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