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blagie [28]
3 years ago
8

Can you find the slope-intercept equation of each line and type the correct code? Please remember to type in ALL CAPS with no sp

aces.

Mathematics
1 answer:
natali 33 [55]3 years ago
4 0

Answer:

The code is AEBG

Step-by-step explanation:

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what is the answer to the volleyball team at blue point high school has saved $680 and the team plans to spend no more then that
Oliga [24]

Answer:

Step-by-step explanation:

just add the numbers

6 0
4 years ago
What is 5 1/2 of 60%
EleoNora [17]
You mean 60%of 5 1/2? that makes more sense...


i would do it like this:

\frac{60}{100}* 5\frac{1}{2}

(60% is the same as \frac{60}{100}

5\frac{1}{2}=\frac{11}{2}

(so that there is no confusion, i've put it into an improper fraction

now we can multiply:
\frac{60}{100}* \frac{11}{2}=

\frac{6}{10}* \frac{11}{2}=

\frac{3}{5}* \frac{1}{2}=



\frac{3*11}{10}=

\frac{33}{10}=

which is 3.3.

so 60% of 5 and a half is 3.3.


6 0
3 years ago
Special right triangle
Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

6) taking 45 degrees as the reference angle,

the adjacent side is √6

The opposite side is x

The hypotenuse is y

Therefore, we would apply trigonometric ratio.

Tan # = opposite side / adjacent side

Tan 45 = x/√6

1 = x/√6

x = 1 × √6 = √6

Cos # = adjacent side/hypotenuse

Cos 45 = √6/y

Cos 45 expressed in surd form is √2/2. Therefore,

√2/2 = √6/y

y √2 = 2√6

y = (2√6)/√2

5 0
3 years ago
What is the difference of the polynomials? (â€""2x3y2 4x2y3 â€"" 3xy4) â€"" (6x4y â€"" 5x2y3 â€"" y5) â€""6x4y
zlopas [31]

Polynomial-An expression of two or more algebraic terms, which is the sum or difference of the several terms with having different power of the only variable. The difference between the given polynomials is

=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5

Given-

We have given two function of variable <em>x </em>and <em>y</em>

(-2x^3y^2 + 4x^2y^3-3xy^4)

(6x^4y-5x^2y^3-y^5)

<h3>Polynomial</h3>

An expression of two or more algebraic terms, which is the sum or difference of the several terms with having different power of the only variable.

Now we have to subtract the two equations to find the difference,

(-2x^3y^2 + 4x^2y^3-3xy^4)-(6x^4y-5x^2y^3-y^5)

Multiply the sign into the bracket to open the bracket and further solution,

=-2x^3y^2 + 4x^2y^3-3xy^4-6x^4y+5x^2y^3+y^5

Arrange the similar terms in the same groups,

=-2x^3y^2 + (4x^2y^3+5x^2y)-3xy^4-6x^4y+y^5=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5

Hence, the difference between the given polynomials is=-2x^3y^2 + 9x^2y^3-3xy^4-6x^4y+y^5

For more about the polynomials, follow the link below-brainly.com/question/17822016

5 0
3 years ago
How do you solve for the quotient of (x^-1) - 1 ÷ x - 1?
Ber [7]

\bf x^{-1}-1\div x-1\implies \implies \cfrac{1}{x}-1\div x-1\implies \cfrac{\frac{1}{x}-1}{~~x-1~~}\implies \cfrac{~~\frac{1-x}{x}~~}{\frac{x-1}{1}} \\\\\\ \cfrac{1-x}{x}\cdot \cfrac{1}{x-1}\implies \cfrac{-(\begin{matrix} x-1 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix})}{x}\cdot \cfrac{1}{\begin{matrix} x-1 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}\implies -\cfrac{1}{x}\implies -x^{-1}

3 0
4 years ago
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