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Lyrx [107]
4 years ago
12

8 ( j - 4 ) = 2(4j - 16 )

Mathematics
2 answers:
Tanya [424]4 years ago
7 0
8j-32=8j-32
J=j
Js value is infinite
natima [27]4 years ago
5 0
8(j) + 8(-4) = 2(4j) + 2(-16)

8j - 32 = 8j - 32
-8j           -8j

-32 = -32   Infinite many solutions
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Which function has a constant additive rate of change of -1/4?
VladimirAG [237]

Answer:

The first graph (in other words A)

Step-by-step explanation:

bc it is going down 1/4 at a constant rate!!!

Hope This Helps!!!

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3 years ago
Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3
LekaFEV [45]

Answer:

(a)\ \sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128} = 8 \sqrt{2}

Step-by-step explanation:

Required

Simplify

(a)\ \sqrt{20}

Express 20 as 4 * 5

\sqrt{20}=\sqrt{4 * 5}

Split

\sqrt{20}=\sqrt{4} * \sqrt{5}

This gives:

\sqrt{20}=2 * \sqrt{5}

\sqrt{20}=2\sqrt{5}

(b)\ \sqrt{300

Express as 100 * 3

\sqrt{300} = \sqrt{100} * \sqrt{3}

This gives:

\sqrt{300} = 10 * \sqrt{3}

\sqrt{300} = 10 \sqrt{3}

(c)\ \sqrt{128}

Express as 64 * 2

\sqrt{128} = \sqrt{64*2}

Split

\sqrt{128} = \sqrt{64} * \sqrt{2}

\sqrt{128} = 8 * \sqrt{2}

\sqrt{128} = 8 \sqrt{2}

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0
3 years ago
What is 4/7 as a decimal
scoundrel [369]

Answer:

0.57142858 is the answer hope this helped



7 0
3 years ago
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MrRa [10]

9/40 + 2/40 = 11/40

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3 years ago
Solve for y. 3/2x-3y=6
Vlada [557]
X=2(2+y) is your answer
3 0
3 years ago
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