Mason throws a coin 3 times.
1 answer:
Given:
Mason throws a coin 3 times.
The outcome of each throw is either Heads or Tails.
To find:
The list of all the possible outcomes of the 3 throws.
Solution:
Let H represents heads and T represents tails.
For each throw we have 2 choices either H or T.
For three throws the total number of possible outcomes is
Now, list the possible outcomes as shown below.
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
Therefore, the list of 8 possible outcomes is HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.
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Answer:
The value of n is 21.
Step-by-step explanation:
We are given that three of the exterior angle of the n-sided polygon are 50° each two of its interior angle are 127° and 135° and the remaining interior angle are 173 each.
As we know that the sum of all exterior angles of the polygon is 360°. Also, the number of remaining interior angles will be (n - 5).
And, the exterior angle = 180° - the interior angle.
So, according to the question;
150 + 53 + 45 + 7(n - 5) = 360
248 + 7n - 35 = 360
213 + 7n = 360
7n = 360 - 213
7n = 147
n =
n = 21
Hence, the value of n is 21 and this is a 21-sided polygon.