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3 years ago

For the polynomial 8x3y2 – x?y2 + 3xy2 – 4y3 to be fully simplified and written in standard form, the missing exponent on the

2 answers:

6 0

A polynomial in standard form has terms arranged with the highest exponent on leftmost side and the lowest exponent on the right end. The variables are also arranged alphabetically.

Therefore, the exponent of the x-term must be 2 for the polynomial to be fully simplified and written in standard form.

Karo-lina-s [1.5K]3 years ago

5 0

Answer: 2

Step-by-step explanation: this answer is 100% correct for edge.nuity

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a CD usally sells for 14.00 if the CD is 30% off and sales tax7% whats the total price of the price of the CD including tax

Ostrovityanka [42]

First you will get the sale price.

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then multiply the CD price by the decimal

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3 years ago

What is the polynomial function of lowest degree with lead coefficient 1 and roots 1 and 1 + i? f(x) = x2 – 2x + 2 f(x) = x3 – x

konstantin123 [22]

Answer:

$f(x)=x^{3}-3x^{2} +4x-2$

Step-by-step explanation:

we know that

The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial

In this problem we have that

The polynomial has roots 1 and (1+i)

by the conjugate root theorem

(1-i) is also a root of the polynomial

therefore

The lowest degree of the polynomial is 3

$f(x)=a(x-1)(x-(1+i))(x-(1-i))$

Remember that

The leading coefficient is 1

a=1

$f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2$

5 0

3 years ago

Read 2 more answers