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3 years ago

6

For what value of x does 3^2x-9^3x-4

1 answer:

Sever21 [200]3 years ago

8 0

Answer:

jdjndbncjjsnnxjjxjnxjnsnnx.

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9m+14=2m How do I solve and check answer?

Lorico [155]

9m+14=2m
9m-2m= -14
7m = -14
m= -2

to check: u need to chance the m to -2
9m - 2m= -14
9 × -2= -18
-2 × -2= -4
-18 - (-4)= -14
i think is right

8 0

3 years ago

Write the amount as a fraction of a dollar, as a decimal, and as a money amount.

sergey [27]

6/10
0.6
60 cents

17/100
0.17
17 cents

49/100
0.49
49 cents

92/100
0.92
92 cents

6 0

3 years ago

Read 2 more answers

How to find the volume of the cone

gavmur [86]

Answer:

The closest measurement to the volume of hat is 84.82 in.³.

Step-by-step explanation:

Given:

The dimensions of hat are height(h) 9 inches and diameter(d) 6 inches.

Now, to find the volume of cone:

Putting the formula $\frac{1}{3}\pi r^{2}h$ .

Radius(r) is not given, finding the radius:

Radius(r)=half of the diameter(d)

$r=\frac{d}{2}$

$r=\frac{6}{2}$

$r=3$ .

Then, $\frac{1}{3}\pi r^{2}h$

= $\frac{1}{3}\times\pi \times3^{2}\times9$

= $\frac{1}{3}\times3.14\times9\times9$ ( $\pi =3.14$ )

= $\frac{1}{3} \times254.34$

= $\frac{254.34}{3}$

= $84.78$ in.³

So, the volume is 84.78 in.³ .

Therefore, the closest measurement to the volume of hat is 84.82 in.³.

5 0

3 years ago

Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc

Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when $M = 0.3, \sigma = 4.103$ . So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.3 = 1.96*\frac{4.103}{\sqrt{n}}$

$0.3\sqrt{n} = 1.96*4.103$

$\sqrt{n} = \frac{1.96*4.103}{0.3}$

$(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}$

$n = 718.57$

Rouding up

We need a sample size of at least 719

6 0

3 years ago

Joanie runs the concession stand for the school's baseball games. At each game, the best selling items are pretzels and hot dogs

STALIN [3.7K]

77 because add them all up then subtract 14

3 0

3 years ago