Answer:
The product of
is 81.6
Step-by-step explanation:
Given : 
To Find : Find the product
Solution:


So, 

Hence the product of
is 81.6
Answer:
we choose (3,4)
Step-by-step explanation:
Given the coordinates:
- A (5, 2)
- B (5, -2)
- C (2,1)
- L (-5, 6)
- M (-5, -6)
To find a distance between two points or the length of the segment, we use the following formula:

- Because A and B are located in the same line x =5
=> the lenght of AB =
- Because A and B are located in the same line x =-5
=> the lenght LM =
- Because ABC is similar to LMN
=> the ratio of LM : AB = 12:4 = 3:1
<=> the ratio LN : CA = 3:1
We need to find the lenght of CA
=
=> the lenght of LN = 3CA = 3
Let (x, y) is the coordinate of N, we have:
The length of LN:
=
Let try all the possible answer;
(3,4) =>
True
So we choose (3,4)
Answer:
x = 12
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the opposite interior angles
10x-10 = 60 +4x+2
Combine like terms
10x-10 = 62+4x
Subtract 4x from each side
10x-4x -10 = 62 +4x-4x
6x -10 = 62
Add 10 to each side
6x-10+10 = 62+10
6x= 72
Divide by 6
6x/6 = 72/6
x = 12
Answer:
(9159 / 7 = 1308.429)
Step-by-step explanation:
Simply multiply the last digit by 2 and then subtract the product from the remaining digits.
If that difference is divisible by 7, then 9159 is divisible by 7.
The last digit in 9159 is 9 and the remaining digits are 915. Thus, the math to determine if 9159 is divisible by 7 using our alternate method is:
915 - (9 x 2) = 897
Since 897 is not divisible by 7, 9159 is also not divisible by 7.
Therefore, the answer to "Is 9159 Divisible By 7?" is no.
(9159 / 7 = 1308.429)
The answer is 11 i
<em /><em>Explanation:
</em>
The square root needs to be a number that can be multiplied by itself and equal the original number.
In this case, the number is 11, 11*11 = 121
However, you are looking for the square root of a negative number, due to this you would add i to the answer,
i = imaginary number, or -
( Depending on your grade/ teacher however, you can put "no solution"