Work shown above! Answer is
a = 5 b = -2 c = 0
Answer:
x(3 + 9) = 3x + 9x = 12x
Step-by-step explanation:
...........
Answer:416
Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
