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Assoli18 [71]
2 years ago
6

The class party started with five chocolate cakes cut in fourths as shown below in the example.

Mathematics
1 answer:
professor190 [17]2 years ago
5 0
<h3>Answer:     7/20</h3>

============================================================

Explanation:

One large square cake cuts into 4 smaller slices

Since we have 5 such cakes that are cut like this, we have 5*4 = 20 slices all together.

Count the number of dark shaded slices that are shown in the lower diagram. We have 4+3+4+2 = 7+6 = 13 slices of cake that are left over. This must mean the class ate 20-13 = 7 slices.

The fraction of the cakes eaten is 7/20

Notes:

  • 7/20 = 35/100 = 0.35 = 35%
  • The fraction 7/20 cannot be reduced further because 7 and 20 have no common factors other than 1.
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Solve with cramer's rule x+2y+3z=11, 2x+y+2z=10, 3x+2y+z=9
nalin [4]

Answer:

x = 2 , y = 0 , z = 3

Step-by-step explanation:

Cramer's rule is a rule through which we can find the solution of linear equation.

we have the three linear equations as

x+2y+3z=11

2x+y+2z=10

3x+2y+z=9

AX=B  

A: coefficient matrix

X= unknown vectors(x,y,z)

D = values of the linear equation (11 , 10 , 9)

now we find the determinant of the given linear equation

determinant of the matrix will be

A = \left[\begin{array}{ccc}1&2&3\\2&1&2\\3&2&1\end{array}\right]  = 1(1-4) - 2(2-6) + 3(4 - 3)

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also D\neq 0

so the determinant is Non zero we can apply Cramer's rule

we will be replacing the first column of the coefficient matrix A with the values of D

by replacing the first column we will get the value of the variable 'x'

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so we have the solution as

x = 2 , y = 0 , z = 3

Therefore the solution for the given linear equations is (2,0,3).

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