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3 years ago

Question 3

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

5 0

Answer:

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Step-by-step explanation:

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Sage and Tom started the month with the same number of talk minutes on their cell phones. Sage talked for 7 minutes with her dad

Paraphin [41]

Answer:

a. Sage and Tom have the same number of talk minutes left on their cell phone plans.

b. y = x - 7

Explanation:

Sage talked for 7 minutes with her dad.

Tom talked for 4 minutes with a friend and 3 more minutes with his mom which means he spoke for :

= 4 + 3

= 7 minutes

They both spoke for 7 minutes and therefore have the same amount of time left.

Algebraic expression:

Assuming the time Tom started with is denoted by x and the time he is left with is denoted by y.

The expression is:

y = x - 7

6 0

3 years ago

(24 ÷ 6 - 2 + 5 × 3 × (-1 - 3) ÷ 4)^2 How do you solve this? Help me I need this ASAP!!

Bond [772]

Answer:

169

Step-by-step explanation:

PEMDAS

Parenthesis first

Add -1 and -3 which is -4

Divide 24 by 6 which is 4

(4-2+5*3*-4÷4)^2

(4-2-15)^2

(2-15)^2

(-13)^2

Which is 169

6 0

2 years ago

What is step 2 in the problem solving process?

Vlada [557]

Answer:

read the problem

Step-by-step explanation:

a. write down the facts and figures

b. read the problem

c. find a relationship between what is given and what must be found

d. do the work

5 0

3 years ago

Read 2 more answers

#18 help ASAP I have a quiz tomorrow!!!!!

Brut [27]

Answer:

$320

Step-by-step explanation:

Please see attached picture for full solution.

8 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago