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pogonyaev
3 years ago
5

What is the value of the product (3 – 21)(3 + 2/)? 5 9 + 4 9 - 41 13

Mathematics
1 answer:
Nuetrik [128]3 years ago
5 0

Answer:

<em>t</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>-</em><em>9</em><em>0</em>

Step-by-step explanation:

hope it helps

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Answer:

3 (a-2) (a-5)

Step-by-step explanation:

The first step is to find the GCF. Here, it's 3.

3(a^2-7a+10)

Then, you factor the polynomial in the parenthesis.

To find the factors, you will need to find 2 numbers that add to -7, and multiply to 10. -2 and -5 add to -7 and multiply to 10. Now, replace -7a with the factors.

a^2-2a-5a+10

This of this polynomial as 2 problems.

a^2-2a        -5a+10

Then, factor again.

a^2-2a        -5a+10

a(a-2)       -5(a-5)

Then, you keep the factors in parenthesis, and combine the numbers on the outside.

(a-2)(a-5)(a-5)

Since, there are 2 of the same factor, you only need one.

(a-2)(a-5)

BUT REMEMBER!! In the very beginning, we had a 3 that we took out, we STILL need to add that to the final answer. The <u>final answer</u> is:

3 (a-2) (a-5)

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