What is the value of the product (3 – 21)(3 + 2/)? 5 9 + 4 9 - 41 13

Mathematics

1 answer:

Nuetrik [128]4 years ago

5 0

Answer:

the correct answer is -90

Step-by-step explanation:

hope it helps

You might be interested in

Which points is of the ordered pair (-4,2)

avanturin [10]

Answer:2-4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Simplify.

lubasha [3.4K]

(-1/2)(4)(-2)(7y)(-1)

Just start multiplying!

-1/2 * 4 = -2
-2 * -2 = 4
4 * 7y = 28y
28y * -1 = -28y

Since that's not an option I suspect you're missing an x.

7 0

3 years ago

What times what equals 52 in mixed fractions

Softa [21]

To do this, we calculated all possible solutions to this problem:

what x what = 52

Note that "what" and "what" in the above problem could be the same number or different numbers.

Below is a list of all the different ways that what times what equals 52.

1 times 52 equals 52

2 times 26 equals 52

4 times 13 equals 52

13 times 4 equals 52

26 times 2 equals 52

52 times 1 equals 52

7 0

4 years ago

Read 2 more answers

Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8

Delvig [45]

We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51$

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22$

Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98$

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = $m-z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Lower end of confidence interval= $123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34$
Upper end of confidence interval = $m+z *\frac{psd}{ \sqrt{n} }$
Using the values, we get:
Upper end of confidence interval= $123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86$

Thus the 98% confidence interval will be (105.34, 141.86)

Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.

3 0

4 years ago

I’m not sure what I’m doing here done everything they say to do but I keep getting it wrong pls explain

Marysya12 [62]

Answer:

I'm pretty sure the peremiter is 466 ft.

3 0

3 years ago